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soldi70 [24.7K]
3 years ago
9

What mass of water must evaporate from the skin of a 70.0 kg man to cool his body 1.00 ∘C? The heat of vaporization of water at

body temperature (37.0 ∘C) is 2.42×106J/(kg⋅K). The specific heat of a typical human body is 3480 J/(kg⋅K) . What volume of water must the man drink to replenish the evaporated water?
Physics
1 answer:
romanna [79]3 years ago
6 0

Answer:

100 cc

Explanation:

Heat released in cooling human body by t degree

= mass of the body x specific heat of the body x t

Substituting the data given

Heat released by the body

= 70 x 3480 x 1

= 243600 J

Mass of water to be evaporated

= 243600 / latent heat of vaporization of water

= 243600 / 2420000

= .1 kg

= 100 g

volume of water

= mass / density

= 100 / 1

100 cc

1 / 10 litres.

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Explanation:

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A ball is attached to a vertical spring. The ball is initially supported at a height y so that the spring is neither stretched n
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Answer:

All the three quantities will have non zero joules.

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29 m/s.

Explanation:

Hope this helps.

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A firefighter of mass 81 kg slides down a vertical pole with an acceleration of 3 m/s 2 . The acceleration of gravity is 10 m/s
natima [27]

Answer:

The force of friction that acts on him is

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Explanation:

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4 0
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Which of the following is considered a physical change? burning paper rusting of metal evaporating water
alex41 [277]

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When iron rusts, or copper or silver turns green, that's the result
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6 0
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