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ELEN [110]
2 years ago
10

Find the magnitude of a fourth force on the stone that will make the vector sum of the four forces zero.

Physics
1 answer:
Tanya [424]2 years ago
7 0
100cos30° + 80cos120° + 40cos233° + Dx = 0 
<span>Dx = -22.53 N </span>

<span>y components: </span>
<span>100sin30° + 80sin120° + 40sin233° + Dy = 0 </span>
<span>Dy = -87.34 N </span>

<span>magnitude of D: </span>
<span>sqrt[(-22.53)² + (-87.34)²] </span>
<span>90.2 N </span>

<span>direction of D: </span>
<span>arctan[(-87.34)/(-22.53)] </span>
<span>75.5° ref, but since Dx and Dy are both negative, we know this vector is in QIV: </span>
<span>360 - 75.5° = 284.5°</span>
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