Answer:
it's C.
Step-by-step explanation:
Hope that helped :D
Answer:
7 or 8
Step-by-step explanation:
Robbie was given $80.
His admission costs $15.50
80 - 15.50 = $64.50
He anticipates the cost of food at the fair will be $25.
64.50 - 25 = $39.50
What is the maximum number of rides he can take at the Fair?
(Total $ after admission and cost of food/ ride cost)
$39.50 / $5 = 7.9
Answer:
76%
Step-by-step explanation:
So basically 528 represents a full circle and the amount in the circle is 2:5 to that in the stalls.
So you divide 528 by 2 and then multiply it by 5 to get a full stall of 1320
you then add 1320 and 528 to get a full theater of 1848
to get 2/3 of seats in the stall you divide 1320 by 3 and then multiply it by 2 to get 880.
For 2/3 of the stall and a full circle you add 880 and 528 to get 1408.
You divide the amount of people in the theater on Friday by the total amount of people which the theater can hold so 1408 divided by 1848 and you get the percentage of 76%
If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
At least 5. because 47x4=188 which isn’t enough money, and 47x5=235, which goes over but you have to have more money than less money
