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inysia [295]
3 years ago
6

A partnership between a gaming company and moviemakers might happen in what two ways?

Engineering
1 answer:
Allisa [31]3 years ago
6 0

Answer:

1. The gaming company installs games for an arcade in the set of a movie

2. moviemakers might give permission to make a game based on the movie.

3. Advertisements on a game the moviemakers might get a percentage of the money made on a game because there are characters from the movie on the box saying "I played this game and it was awesome,"

Hope this helped! :)

Explanation:

You might be interested in
A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 30.00 a
kirill [66]

Answer:

105.70 mm

Explanation:

Poisson’s ratio, v is the ratio of lateral strain to axial strain.

E=2G(1+v) where E is Young’s modulus, v is poisson’s ratio and G is shear modulus

Since G is given as 25.4GPa, E is 65.5GPa, we substitute into our equation to obtain poisson’s ratio

\begin{array}{l}\\65.5{\rm{ GPa}} = 2\left( {25.4{\rm{ GPa}}} \right)(1 + \upsilon )\\\\\upsilon = 0.2893\\\end{array}

Original length L_(i}

\upsilon = - \left( {\frac{{\left( {\frac{{{d_f} - {d_i}}}{{{d_i}}}} \right)}}{{\left( {\frac{{{L_f} - {L_i}}}{{{L_i}}}} \right)}}} \right)

Where d_{f} is final diameter, d_{i} is original diameter, L_{f} is final length and L_{i} is original length.

\begin{array}{l}\\0.2893 = - \left( {\frac{{\left( {\frac{{30.04{\rm{ mm}} - {\rm{30 mm}}}}{{{\rm{30 mm}}}}} \right)}}{{\left( {\frac{{{\rm{105.2 mm}} - {L_i}}}{{{L_i}}}} \right)}}} \right)\\\\\left( {\frac{{{\rm{105.2 mm}} - {L_i}}}{{{L_i}}}} \right) = - 4.6088 \times {10^{ - 3}}\\\end{array}

\begin{array}{l}\\105.2 - {L_i} = - \left( {4.6088 \times {{10}^{ - 3}}} \right){L_i}\\\\105.2 = 0.9953{L_i}\\\\{L_i} = 105.70{\rm{ mm}}\\\end{array}

Therefore, the original length is 105.70 mm

7 0
4 years ago
A) Describe the operation of a heat pump operating on the theoretical reversed Carnot cycle, with a neat sketch of the layout.
kicyunya [14]

Answer:

a) The operation of a heat pump involves the extraction of energy in the form of heat Q₁ from a cold source

b) The modifications required to convert a plant operating on an ideal Carnot cycle to a plant operating on a Rankine cycle involves

i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler

ii) Heating of the pumped, pressurized water to the boiler pressure

Explanation:

a) 1 - 2. Wet vapor enters compressor where it undergoes isentropic compression to state 2 by work W₁₂  

2 - 3. The vapor enters the condenser at state 2 where it undergoes isobaric and isothermal condensation to a liquid with the evolution of heat  Q₂

3 - 4. The condensed liquid is expanded isentropically with the work done equal to W₃₋₄

4 - 1. At the state 4, with reduced pressure from the previous expansion, the liquid makes its way to the evaporator where it absorbs heat, Q₁, from the body to be cooled.

b. i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler

Here the condensation process is modified from partial condensation to complete condensation at the same temperature which reduces the size of the pump required to pump the liquid water as opposed to pumping steam plus liquid

ii) Heating of the pumped, pressurized water to the boiler pressure

The pumped water at state 4 will be required to be heated to saturated water temperature equivalent to the boiler pressure, hence heat will need to be added at state.

Sketches of the schematic of a Basic Rankine cycle is attached  

3 0
3 years ago
Consider an electric motor with a shaft power output of 20 kW and an efficiency of 88 percent. Determine the rate at which the m
Eduardwww [97]

Answer:

Rate of heat dissipation = 2.4 kW,

When the engine operates at complete load, it would not be essential to switch the heater on. As, the level of engine heat dissipation is higher than the heat dissipation level per heater.

Explanation:

The rate of heat dissipation = (total\ output\ power \times( 1- efficiency))

Rate of heat dissipation= 20 kW ( 1-0.88)

Rate of heat dissipation = 2.4 kW,

For , room heating if heat required is 2 kW,

Then ,

When the engine operates at complete load, it would not be essential to switch the heater on. As, the level of engine heat dissipation is higher than the heat dissipation level per heater.

8 0
3 years ago
A rigid tank with a volume of 2.5 contain 15 kg of saturated liquid
Novosadov [1.4K]

Answer:

A rigid tank with a volume of 2.5 m 3 contains 15 kg of saturated liquid–vapor mixture of water at 75°C. Now the water is slowly heated. Now the water is slowly heated. Determine the temperature at which the liquid in the tank is completely vaporized.

8 0
3 years ago
Provide relevant parts of C-like codes for processes X1, X2, X3, X4 and X5 in the following synchronization problem. Each proces
labwork [276]

Answer:

import java.util.concurrent.Semaphore;

public class synchronization implements Runnable {

Semaphore b11 = new Semaphore(1);

@Override

//run method

public void run() {

boolean flvalue=false;

System.out.println("Started");

while(!flvalue) {

System.out.println("Thread is running");

}

System.out.println("Stopped");

}

//main method

public static void main(String args[]) {

final synchronization t11 = new synchronization();

Thread x1=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x2=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x3=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x4=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

Thread x5=new Thread(){

@Override

//run method

public void run(){

t11.mutualExclusion();

}

};

x1.start();

x2.start();

x3.start();

x4.start();

x5.start();

 

}

private void mutualExclusion() {

try {

b11.acquire();

//mutual value

String tn=Thread.currentThread().getName();

String numberOy= tn.replaceAll("[^0-9]", "");

int num=Integer.parseInt(numberOy)+1;

System.out.println("Thread "+num + " is running");

Thread.sleep(100);

} catch (InterruptedException ie11) {

ie11.printStackTrace();

} finally {

b11.release();

String tn11=Thread.currentThread().getName();

String numberOy= tn11.replaceAll("[^0-9]", "");

int numval=Integer.parseInt(numberOy)+1;

System.out.println("Thread "+numval + " completed...!!!");

}

}

 

}

Explanation:

3 0
3 years ago
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