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RSB [31]
4 years ago
5

A cannon ball is fired with an arching trajectory such that at the highest point of the trajectory the cannon ball is traveling

at 98 m/s. If the acceleration of gravity is 9.81 m/s^2, what is the radius of curvature of the cannon balls path at this instant?
Engineering
1 answer:
ELEN [110]4 years ago
8 0

Answer:

The radius of curvature is 979 meter

Explanation:

We have given velocity of the canon ball v = 98 m/sec

Acceleration due to gravity g=9.81m/sec^2

We know that at highest point of trajectory angular acceleration is equal to acceleration due to gravity

Acceleration due to gravity is given by a_c=\frac{v^2}{r}, here v is velocity and r is radius of curvature

So \frac{98^2}{r}=9.81

r = 979 meter

So the radius of curvature is 979 meter

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• Suppose that a particular algorithm has time complexity T(n) = 10 ∗ 2n, and that execution of the algorithm on a particular ma
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A circuit contains a resistor, an inductor, and a capacitor. When an AC voltage is applied across the circuit, the impedance of
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Answer:

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