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julia-pushkina [17]
3 years ago
12

Estimate the quantity of soil to be excavated from the borrow pit​

Engineering
1 answer:
Serggg [28]3 years ago
6 0

Answer

1056

Explanation:

for example

A soil is to be excavated from a borrow pit which has a density of 1.75g/cc and water content of 12%. The G is 2.7 the soil is compacted to that water content of 18% and dry density of 1.65g/cc. for 1000 m3 of soil used in fill estimate

Quantity of soil to be excavated from pit in m3

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A rectangular bar of length L has a slot in the central half of its length. The bar has width b, thickness t, and elastic modulu
Naya [18.7K]

Answer:

The correct answer to the following question will be "1.23 mm".

Explanation:

The given values are:

Average normal stress,

\sigma=200 \ MPa

Elastic module,

E = 77 \ GPa

Length,

L = 570 \ mm

To find the deformation, firstly we have to find the equation:

⇒  \delta=\Sigma\frac{N_{i}L_{i}}{E \ A_{i}}

⇒     =\frac{P(\frac{L}{H})}{E(bt)} +\frac{P(\frac{L}{2})}{E (bt)(\frac{2}{3})}+\frac{P(\frac{L}{H})}{Ebt}

On taking "\frac{PL}{Ebt}" as common, we get

⇒     =\frac{\frac{PL}{Ebt}}{[\frac{1}{4}+\frac{3}{4}+\frac{1}{4}]}

⇒     =\frac{5PL}{HEbt}

Now,

The stress at the middle will be:

⇒  \sigma=\frac{P}{A}

⇒     =\frac{P}{(\frac{2}{3})bt}

⇒     =\frac{3P}{2bt}

⇒  \frac{P}{bt} =\frac{2 \sigma}{3}

Hence,

⇒  \delta=\frac{5 \sigma \ L}{6E}

On putting the estimated values, we get

⇒     =\frac{5\times 200\times 570}{6\times 77\times 10^3}

⇒     =\frac{570000}{462000}

⇒     =1.23 \ mm  

8 0
3 years ago
Structural engineers, designing an eighty-story office building, need to account for sway. They would most likely use a(n) ____
tia_tia [17]

Answer:

I would say a level

Explanation:

A level is used as a horizontal reference line, which will tell if the building is leaning to one side, or if its up right. I may be wrong but this is the closest thing I can think of for this question.

8 0
3 years ago
The SDS for any chemical used at a job site must be available
NISA [10]

Answer:

<em>Hello There The Correct Answer is </em>A. At The Job Site.

Explanation:

Because the SDS must not used any kind of chemical Most chemicals used in the workplace have some hazard potential, and thus will be covered by the rule. ... Chemical manufacturers, importers, and distributors of hazardous chemicals are all required to provide the appropriate labels and material safety data sheets to the employers to whom they ship the chemicals. So That why is Opinion A.

3 0
3 years ago
Read 2 more answers
On-site oil storage containers must be marked “Used Oil.”<br> True<br> False
Mice21 [21]

Answer:

true

Explanation:

cause it said on site

8 0
3 years ago
If a material is found to be in the tertiary phase of creep, the following procedure should be implemented:
kirill [66]

When a material is found to be in the tertiary phase of creep, the following procedure should be implemented that is the component should be replaced immediately. Therefore, Option C is correct.

<h3>What do you mean by a tertiary degree of creep?</h3>

Tertiary Creep has an extended creep rate and terminates when the material breaks or ruptures. It is related to each necking and formation of grain boundary voids. The wide variety of possible stress-temperature- time combos is infinite.

Therefore, When a material is found to be in the tertiary phase of creep, the following procedure should be implemented that is the component should be replaced immediately. Option C is correct.

Learn more about creep:

brainly.com/question/10565749

#SPJ1

8 0
2 years ago
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