If you're just integrating a vector-valued function, you just integrate each component:
The first integral is trivial since 
.
The second can be done by substituting 
:
The third can be found by integrating by parts:
Answer:
where is the figure?
Step-by-step explanation:
For question 4: you have to do (y2 - y1) divided by (x2 - x1) to get the rise over run...
5-2
——. = 3/4
11 - 7
For question 5: input the values of x,y and the gradient into the equation of a line.....
y = mx+ c
-8 = 3(-2) + c
-8 = -6 + c
-2 = c
therefore:
y = 3x - 2
Hope this helps! Any questions let me know :)
On your calculator, use the normalcdf() function, enter the Lower Limit, Upper Limit, Mean, and Standard deviation.
The mean and standard deviation are given to you. You want to find "less than 13.5 seconds", meaning that 13.5 is the maximum "Upper Limit" and 0 would be the Lower Limit because we can pretend 0 second is the minimum. Don't worry about negatives, in this scenario, values like "-5 seconds" are impossible.
Enter normalcdf(0, 13.5, 13.56, 2.24) in a calculator and the output result is the answer.
The answer to the question is 6 yards and 2 feet
