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kvv77 [185]
3 years ago
7

Jonathan bought a new computer for $1,716, using the electronics store's finance plan. He will pay $143 a month for 12 months. W

hich equation can Jonathan use to find out how much money he still owes after each month of the plan?
Group of answer choices

y=143x-1,716

y=1,716-143x

y=1,716+143x

y=143x
Mathematics
2 answers:
Reptile [31]3 years ago
7 0
He would use y=1,716-143x
Fofino [41]3 years ago
6 0

y=1,716+143 ok got it

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The second statement is the what of the first?
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Answer:

  contrapositive

Step-by-step explanation:

The <u>converse</u> statement would be ...

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The <u>contrapositive</u> swaps the parts and negates them both:

  ¬b ⇒ ¬a . . . . . matches your given statement

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A <u>contradiction</u> arises when the implication is false: a is true and b is false.

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Keith bake 3 cherry pies and 2 apple pies.He wants to share each pie equally among 6 of his neighbors. How much of each type of
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Each neighbor will get 1/2 of the cherry pie and 1/3 of the apple pie.
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Anon25 [30]
11/12 is the greater fraction.

2/60
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\large\underline{\sf{Solution-}}

<u>Let us assume that:</u>

\sf \longmapsto x =  \sqrt{6 +  \sqrt{6 +  \sqrt{6 + ... \infty } } }

We can also write it as:

\sf \longmapsto x =  \sqrt{6 +  x }

Squaring both sides, we get:

\sf \longmapsto  {x}^{2}  =6 +  x

\sf \longmapsto  {x}^{2} - x - 6  =0

By splitting the middle term:

\sf \longmapsto  {x}^{2} - 3x + 2x - 6  =0

\sf \longmapsto x(x - 3) + 2(x - 3 ) =0

\sf \longmapsto (x+ 2)(x - 3 ) =0

<u>Therefore:</u>

\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}

\sf \longmapsto x =  - 2,3

<u>But x cannot be negative. </u>

\sf \longmapsto x = 3

Therefore, the value of the expression is 3.

\large\underline{\sf{Verification-}}

Given:

\sf\longmapsto x=3

We can also write it as:

\sf\longmapsto x = \sqrt{9}

\sf\longmapsto x = \sqrt{6+3}

\sf\longmapsto x = \sqrt{6 + \sqrt{9}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}

This pattern will continue.

\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}

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Company A:
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