group 1 elements are metals with<u> low</u> density
Answer:
72.2 ml
Explanation:
The neutralization equation between HBr (acid) and NaOH (base) is the following:
HBr(aq) + NaOH(aq) → NaBr(aq) + H₂O(l)
We can see that 1 mol of HBr reacts with 1 mol of NaOH. At the equivalence point, the total number of moles of HBr reacts with the total number of moles of NaOH. The number of moles can be calculated as the product between the molarity (M, in mol/L) and the volume (V). So, we can equal the quantities of acid and base, as follows:
moles HBr = moles NaOH
M(HBr) x V(HBr) = M(NaOH) x V(NaOH)
Now, we calculate the volume of NaOH with the data:
V(NaOH)= M(HBr) x V(HBr)/M(NaOH)
= (2.60 mol/L x 50.0 ml)/(1.80 mol/L)
=72.2 ml
<h3>Answer :</h3>
<h3>Specific Heat</h3>
<h3>Explanation :</h3>
<h3>The specific heat represents the amount of energy required to raise 1 kg of substance by 1oC (or 1 K), and can be thought of as the ability to absorb heat. The SI units of specific heats are J/kgK (kJ/kgoC). Water has a large specific heat of 4.19 kJ/kgoC compared to many other fluids and materials.</h3>
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The answer is d noble gas because the very last column on the periodic table is all the noble gases