Answer:
It is necessary to use models to study sub- microscopic objects such as atoms and molecules because they are too small to be seen.
Answer:

Explanation:
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In this case, according to the given information, it turns out possible for us to solve this problem by firstly setting up the equilibrium expression for the given reaction, in agreement to the law of mass action:
![K=\frac{[NO]^2}{[N_2][O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%7D)
Next, we plug in the given concentrations on the data table to obtain:

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Answer:
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Tantalum is the 73rd element in the periodic table with an atomic mass equal to 180.95 g/mol. To determine the number of moles present in the given mass of tantalum above, we simply divide the mass by the atomic mass.
number of moles = (0.0073 kg)(1000 g/ 1kg) ÷ (180.95 g/mol)
number of moles = 0.0403 moles
Therefore, there is approximately 0.0403 moles of tantalum in 0.0073 kg.