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Ber [7]
3 years ago
7

Complete the chart. (Remember to enter a "0" if necessary.) Atomic Number: 10 1s: 2s: 2p: 3s: 3p: 4s: 3d: 4p: 5s:

Chemistry
1 answer:
ASHA 777 [7]3 years ago
7 0
First, we determine how many electrons can each subshell hold:
s can hold 2 electrons
p can hold 6 electrons
d can hold 10 electrons
f can hold 14 electrons

Second, we start distributing the 10 electrons on the orbitals of subshells based on the arrangement shown in the question :
1s will hold 2 electrons
2s will hold 2 electrons
2p will hold 6 electrons
All other orbitals will will hold zero electrons as the 10 were distributed among the first 2

Answer: 1s: 2
              2s: 2
              2p: 6 
<span>              3s: 0
              3p: 0
              4s: 0
              3d: 0
              4p: 0
              5s: 0</span>
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3 years ago
A) Find the gas speed of sulfur dioxide at 100.0 degrees Celsius? ______________
gtnhenbr [62]

a. 381.27 m/s

b. the rate of effusion of sulfur dioxide = 2.5 faster than nitrogen triiodide

<h3>Further explanation</h3>

Given

T = 100 + 273 = 373 K

Required

a. the gas speedi

b. The rate of effusion comparison

Solution

a.

Average velocities of gases can be expressed as root-mean-square averages. (V rms)  

\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}

R = gas constant, T = temperature, Mm = molar mass of the gas particles  

From the question  

R = 8,314 J / mol K  

T = temperature  

Mm = molar mass, kg / mol  

Molar mass of Sulfur dioxide = 64 g/mol = 0.064 kg/mol

\tt v=\sqrt{\dfrac{3\times 8.314\times 373}{0.064} }\\\\v=381.27~m/s

b. the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

M₁ = molar mass sulfur dioxide = 64

M₂ =  molar mass nitrogen triodide = 395

\tt \dfrac{r_1}{r_2}=\sqrt{\dfrac{395}{64} }=\dfrac{20}{8}=2.5

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3 years ago
Need help with this.
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Answer:

Explanation:

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