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2 years ago

Find the distance between (-3,-11) and (8,-42)

Mathematics

1 answer:

spayn [35]2 years ago

6 0

Answer:

√2930

Step-by-step explanation:

The distance formula is

√((difference between x values)² + (difference between y values)²)

= √((-3 - 8)² + (-11 - (-42))²)

= √((-11)² + (31)²)

= √1082

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How can you find the constant of

solong [7]

Answer:

To find the constant of proportionality from the coordinates of

one point on the graph are as follows :-

1.) Find two easy points.

2.) Start with the leftmost point and count how many squares you need to up to get to your second point.

3.) Count how many squares you need to go to the right.

4.) Simplify, and you've found your constant of proportionality.

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2 years ago

Find the probability of rolling a 6 on a number cube and flipping heads on a coin

serious [3.7K]

Assuming that the number cube is 6 sided

6 is one number in a 6 sided cube, so the probability is: 1/6

heads is one side of the coin, with two in all: 1/2

Multiply the two fractions together

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1/12 is your probability

hope this helps

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3 years ago

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The movie club is having a new member sale, so Mindy signs up. The equation -0.4x + 0.05y - 1.25 = 0 relates y, the total cost,

Wewaii [24]

Answer:

Y intercept : ( 0 , 25 )

Step-by-step explanation:

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2 years ago

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Karen works at a toy story. She has 2 7/8 of marbles . She is making 1/16 pound packages . How many packages will she make?

MArishka [77]

Answer:

46 packages

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3 years ago

If x = a cosθ and y = b sinθ , find second derivative

Olin [163]

I'm guessing the second derivative is for <em>y</em> with respect to <em>x</em>, i.e.

$\dfrac{\mathrm d^2y}{\mathrm dx^2}$

Compute the first derivative. By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$y=b\sin\theta\implies\dfrac{\mathrm dy}{\mathrm d\theta}=b\cos\theta$

$x=a\cos\theta\implies\dfrac{\mathrm dx}{\mathrm d\theta}=-a\sin\theta$

and so

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{b\cos\theta}{-a\sin\theta}=-\dfrac ba\cot\theta$

Now compute the second derivative. Notice that $\frac{\mathrm dy}{\mathrm dx}$ is a function of $\theta$ ; so denote it by $f(\theta)$ . Then

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm dx}$

By the chain rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm df}{\mathrm d\theta}\dfrac{\mathrm d\theta}{\mathrm dx}=\dfrac{\frac{\mathrm df}{\mathrm d\theta}}{\frac{\mathrm dx}{\mathrm d\theta}}$

We have

$f=-\dfrac ba\cot\theta\implies\dfrac{\mathrm df}{\mathrm d\theta}=\dfrac ba\csc^2\theta$

and so the second derivative is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\frac ba\csc^2\theta}{-a\sin\theta}=-\dfrac b{a^2}\csc^3\theta$

4 0

2 years ago