n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
The sample space will be: {1, 2, 3, 4, 5, 6}
Event A is: {Rolling 1,2 or 3}
Complement of event A will contain all those outcomes in the sample space which are not a part of event A.
So, complement of event A will be: {Rolling a 4,5 or 6}
Thus option A gives the correct answer
Answer:
decreasing, then increasing
Answer:
I am attaching a image to understand my proof.
Step-by-step explanation:
PROVE:-
AB = DC
AD = BC
∠ ABD = ∠ BDC (alternate angles are equal )
∠ DBC = ∠ ADB (alternate angles are equal )
∴ Δ ADB ≅ Δ CBD ( by ASA rule )
DC = BA ( corresponding sides of ≅ Δ )
AD = CB ( corresponding sides of ≅ Δ )
Hence it is proved that opposite sides of parallelogram are congruent )
Well according to the slope intercept equation.
Y = mx +/- b
The slope is the value m
The y intercept is b
To graph the function, one sure way to do it is simply make a table of values picking any x values that fall within the graph space, and finding out the resulting y values and using the points to graph.
For instance for the first graph, if x = 0, y = 5, that is one possible point. Keep on choosing x values to graph.
