Where's X located at on the triangle
side a
side b
side c
T(1) = 3, t(n) = -2t(n-1) + 1
So t(2) = -2(t(1)) + 1 = -2(3) + 1 = -5
t(3) = -2(t(2)) +1 = -2(-5) +1 = 11
t(4) = -2(t(3)) +1 = -2(11) +1 = -21
t(5) = -2(t(4)) +1 = -2(-21) +1 = 43
Answer:
3 is continous. 4 is discrete
Step-by-step explanation:
3 houses 2 terms, therefore continuing it. 4 houses 1, stopping the graph.
I might be dumb
