2) deposition and saponification
1. Leave everything alone and don't touch the glass .
2. Tell a Teacher .
3. And that's it .
C because we need materials in the lab
Answer:
The volume will goes to decrease.
Explanation:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
when pressure is going to increase the volume will goes to decrease and vice versa.
Consider the initial volume is 10 L at initial pressure of 15 atm when pressure is increased to 30 atm the volume will be,
Now we will put the values in formula,
P₁V₁ = P₂V₂
15 atm × 10 L = 30 atm × V₂
V₂ = 150 atm. L/ 30 atm
V₂ = 5 L
= 6.42 × 10²²
(scientific notation)
= 6.42e22
(scientific e notation)
= 64.2 × 10²¹
(engineering notation)
(sextillion; prefix zetta- (Z))
= 64200000000000000000000
(real number)
