Answer:
I guess you want to find the lenght of the sides and the other angle, so let's do that:
We know that the base has a length of 14 cm.
The two base angles are 68°
First, we can find the other angle knowing that the sum of all interior angles of a triangle must add up to 180°.
2*68° + X = 180°
X = 180° - 2*68° = 44°
Now let's find the length of the sides (that is the same for both sides, as we have an isosceles triangle.
For this we can draw a line for the middle of the base that goes through the top vertex, creating in this way a triangle rectangle.
We know that one of the cathetus will have half of the length of the base, this is 7cm.
the adjacent angle to this cathetus is 68°, now we want to find the hypotenuse of this triangle, we can use the relation:
Cos(A) = adjacent cathetus/hypotenuse:
Cos(68°) = 7cm/H
H = 7cm/cos(68) = 18.7cm
this hypotenuse is equal to the side length of our isosceles triangle, so now we have it fully determined.
Answer:
1/8
Step-by-step explanation:
Hey there! :)
5n(3n - n + 8)
Simplify.
(5n × 3n) + (5n × -n) + (5n × 8)
Simplify.
(15n²) + (-5n²) + (40n)
Remove parenthesis
**Remember : a negative times a positive is always a negative, a positive times a positive is a positive, and a negative times a negative is a positive**
15n² - 5n² + 40n
Combine like terms.
(15n² - 5n²) + 40n
Simplify.
10n² + 40n → final answer :)
~Hope I helped!~
Answer:
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