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Lunna [17]
4 years ago
11

Does velocity of a wave in a medium changes with the wavelength?

Physics
1 answer:
antoniya [11.8K]4 years ago
4 0
<h2>The velocity of a wave in a medium changes with the wavelength</h2>

Explanation:

Wave

It is the periodic disturbance in a medium.

Types of Wave

There are two types of wave in general depending upon their propagation through a substance.

• Mechanical  

• Electromagnetic  

Mechanical Wave

It is the kind of wave which needs medium to travel.

For example: Sound Wave  

Electromagnetic Wave

Is that which can travel through medium as well as through vacuum. For example: Light

Characteristics of Wave

There are certain characteristics that each sound possesses. Let’s see.  

 Oscillation: It is the complete movement of particle about its mean position.

Amplitude: Is the maximum displacement of particle from its mean position in either direction (cm).It is denoted by ‘A’.

Frequency: It is the number of sound waves produced per second (Hertz).It is denoted by υ(nu)

Time Period: The time taken to complete one oscillation (sec).It is denoted by ‘T’.

Wavelength: The distance between two consecutive crest or trough (cm).It is denoted by λ(lambda).

Velocity of Wave: The speed with which sound travel (m/sec).It is denoted by ‘v’.

Relation between time period, frequency and velocity of wave  

We have: frequency =velocity /wavelength  

                υ=c/λ

Velocity of wave depends upon :

frequency of wave

Wavelength of wave

Therefore , with change in wavelength , the velocity of a wave in medium changes .

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Zero

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A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 cm^2, stands on the floor.An elephant weighing 20
Klio2033 [76]

Answer:

\boxed{{\boxed{\blue{ 12.5}}}}

Explanation:

Given, for girl : Weight or force;

\rm \: F_1 = 50 \: kgf

Area of both heels;

\rm \: A_1 =  \; 2 ×1 \;  cm^2 = 2  \: cm^2

\rm \: Pressure \:  P_1  =  \cfrac{F_1}{ A_1 }  =  \dfrac{50 \: kgf}{2 \: cm {}^{2} }  = 25 \: kgf \: cm {}^{ - 1}

For elephant, Weight = Force \rm F_2 = 2000 kg•f

Area of 4 feet;

\rm \: A_2  = \; 4 \times 250 \;  cm^2 = 1000 \:  cm^2

\rm \: Pressure \:  P_2 = {F_2}/{A_2} \;  = \cfrac{2 \cancel{0 00 }\:  kgf}{1 \cancel{000} \: cm^2} =  2 \: kgf \: { \:cm}^{- 1}

Now;

\rm  = \dfrac{Pressure \:  Exerted  \: by  \: the \:  Girl}{Pressure  \: exerted  \: by \:  the  \: elephant}

=  \rm \: P_1/P_2

\implies    \rm\cfrac{25 \: kgf \: \: cm {}^{ - 2} }{2 \: kgf \: cm {}^{ - 2} } =  \rm\cfrac{25 \:  \cancel{kgf \: \: cm {}^{ - 2}} }{2 \: \cancel{ kgf \: cm {}^{ - 2}} } = \boxed{12.5}

Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.

I aspire this helps!

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