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Mrac [35]
4 years ago
13

The basic function of an automobile carburetor is to atomize the gasoline and mix it with air to promote rapid combustion. Assum

e that 25cm 3 of gasoline is atomized into N spherical droplets. Each droplet has a radius of 1.0 × 10 −5 m. Find the total surface area of these N spherical droplets
Physics
1 answer:
tatyana61 [14]4 years ago
5 0

Answer:

A = 7.5 \times 10^6 m^2

Explanation:

Since volume of all the liquid is always conserved

so here we know that

V_{total} = N V

25 cm^3 = N(\frac{4}{3}\pir^3)

25 = N (\frac{4}{3} \pi (1.0 \times 10^{-5})^3)

N = 5.97 \times 10^{15}

now we know that total surface area is given as

A = N(4\pi r^2)

A = (5.97 \times 10^{15})(4\pi (1 \times 10^{-5})^2

A = 7.5 \times 10^6 m^2

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a water-balloon launcher with mass 4 kg fires a 0.5 kg balloon with a velocity of 3 m/s to the east. what is the recoil velocity
kotykmax [81]
I think we will use the law of conservation of linear momentum;
M1V1 = M2V2
M1 =  4 kg (mass of the water balloon launcher)
V1=?
M2= 0.5 kg ( mass of the balloon)
V2 = 3 m/s

Therefore; 4 V1 = 0.5 × 3
                   4V1= 1.5
                     V1= 1.5/4
                          = 0.375 m/s










5 0
3 years ago
Read 2 more answers
Which example best represents translational kenetic energy
Mila [183]

Answer:

an apple falling off a tree

Explanation:

5 0
3 years ago
The volume of 2.0 kg of helium in a piston-cylinder device is initially 7 m3. Now the helium is compressed to 5 m3 while its pre
IrinaVladis [17]

Answer:

A) T1 = 269.63 K

T2 = 192.59 K

B) W = -320 KJ

Explanation:

We are given;

Initial volume: V1 = 7 m³

Final Volume; V2 = 5 m³

Constant Pressure; P = 160 KPa

Mass; m = 2 kg

To find the initial and final temperatures, we will use the ideal gas formula;

T = PV/mR

Where R is gas constant of helium = R = 2.0769 kPa.m/kg

Thus;

Initial temperature; T1 = (160 × 7)/(2 × 2.0769) = 269.63 K

Final temperature; T2 = (160 × 5)/(2 × 2.0769) = 192.59 K

B) world one is given by the formula;

W = P(V2 - V1)

W = 160(5 - 7)

W = -320 KJ

6 0
3 years ago
water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons​
jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass  and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, T_{(equilibrium)} reached is the same for both the cup and the kettle as given by the relation;

\infty M_{(environ)} \times  c_{(environ)} \times (T_2 - T_1) = m_{1} \times  c_{(water)} \times (T_3 - T_2) + m_{2} \times  c_{(water)} \times (T_4 - T_2)

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

4 0
3 years ago
Why shouldn't we consider the needs of humans first
Orlov [11]

Answer:

We should not consider the needs of humans first because Conservation of nature is more important.

Explanation:

Human beings are important but the priority must be given to nature. Human beings have uncountable needs and if we focus on satisfying all such needs then it will affect our nature. Because finally our needs are fulfilled by using the resources from nature.

So rather than considering the needs of humans first, we must try to preserve our nature as much as possible. It is not done then it will lead to disaster.

8 0
3 years ago
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