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wariber [46]
3 years ago
8

A ball starts from rest and accelerates at 0.460 m/s2 while moving down an inclined plane 8.85 m long. When it reaches the botto

m, the ball rolls up another plane, where, after moving 15.6 m, it comes to rest. What is the speed of the ball at the bottom of the first plane
Physics
1 answer:
Ivahew [28]3 years ago
6 0

Answer:

V=2.8534m/s \approx 3m/s

Explanation:

From the question we are told that

Acceleration a=0.460m/s

Distance traveled S_1=8.5m

Distance traveled S_2=15.6m

Generally the velocity of the ball at the bottom of the first plane V is mathematically given by

v^2=2as

v=\sqrt{2as}

V=\sqrt{2*0.460*8.85}

V=2.8534m/s \approx 3m/s

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