Question

A ball starts from rest and accelerates at 0.460 m/s2 while moving down an inclined plane 8.85 m long. When it reaches the bottom, the ball rolls up another plane, where, after moving 15.6 m, it comes to rest. What is the speed of the ball at the bottom of the first plane

Answer 1

Answer:

$V=2.8534m/s \approx 3m/s$

Explanation:

From the question we are told that

Acceleration $a=0.460m/s$

Distance traveled $S_1=8.5m$

Distance traveled $S_2=15.6m$

Generally the velocity of the ball at the bottom of the first plane V is mathematically given by

$v^2=2as$

$v=\sqrt{2as}$

$V=\sqrt{2*0.460*8.85}$

$V=2.8534m/s \approx 3m/s$