The blank solution used to calibrate the spectrophotometer is 10.0 mL of 0.2 M Fe(NO3)3 diluted to 25.0 mL with 0.1 M HNO3. Why
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The limiting reactant is iron ore, the theoretical yield of iron metal is 701.344 kg, and the theoretical yield of carbon dioxide is 413.292 kg.
<h3>Stoichiometric problem</h3>From the equation of the reaction:
The mole ratio of iron ore to carbon is 2:3.
Mole of 1000 kg of iron ore = 1000000/159.69
= 6,262 moles
Mole of 120 kg carbon = 120000/12
= 10,000 moles
Thus, it appears that the carbon is in excess while the iron ore is limited in availability.
The mole ratio of the iron ore and the iron produced is 1:2. Thus, the equivalent number of moles of iron produced will be:
6,262 x 2 = 12,524 moles
Mass of 12,524 moles of iron = 12,524 x 56
= 701,344 g or 701.344 kg
Thus, the theoretical yield of iron is 701.344 kg.
The mole ratio of the iron ore and the carbon dioxide produced is 2:3. The equivalent mole of carbon dioxide produced will be:
6,262 x 3/2 = 9,393 moles
Mass of 9,393 moles carbon dioxide = 9,393 x 44
= 413,292 or 413.292 kg
The theoretical yield of carbon dioxide is, therefore, 413.292 kg.
More on stoichiometric problems can be found here: brainly.com/question/14465605
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