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Fofino [41]
3 years ago
6

The blank solution used to calibrate the spectrophotometer is 10.0 mL of 0.2 M Fe(NO3)3 diluted to 25.0 mL with 0.1 M HNO3. Why

is this solution preferred to simply using de-ionized water for the calibration?
Chemistry
1 answer:
Sliva [168]3 years ago
4 0
<span>FeNCS+ product...............thats how you do it i believe </span>
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Calculate the molarity a solution that is obtained by dissolving 20 g of KCl in enough water to obtain 355 mL of the solution. A
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Answer:

a) Molarity KCl = 0.755 M

b) molality HNO = 5.09 m

Explanation:

  • Formality (F) = moles sto / L sln
  • Molarity (M) = # dissolved specie / L sln
  • molality (m) = moles sto / Kg ste
  • %p/p = ( g sto / g ste ) * 100

a) KCl ↔ K+  +  Cl-

moles KCL:

⇒ 20 g KCl * ( mol / 74.6 g ) = 0.268 mol KCl

⇒ F = 0.268 mol KCl / 0.355 L = 0.755 F

⇒ M [ K+ ] = 1 * ( 0.755) = 0.755 M

b) 24% HNO:

calculation base: 1 g solution:

⇒24 = ( g sto / g sln) * 100

⇒ 0.24 = g sto / 1

⇒ g sto = 0.24g  

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⇒Kg ste = 0.76 g * ( Kg / 1000g ) = 7.6 E-4 Kg ste

moles sto (HNO):

⇒ 0.24g * ( mol / 62.03g) = 3.869 E-3 moles HNO

⇒ m = 3.869 E-3 moles HNO / 7.6 E-4 Kg sln

⇒ m = 5.09 mol/Kg

3 0
4 years ago
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