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sergey [27]
3 years ago
5

What can the flow of electrons be easily compared to?

Chemistry
1 answer:
julsineya [31]3 years ago
7 0
I think B, the flow of water:))
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You have a cup of tea (250 ml) that is 375 K which is too hot to drink. It needs to be cooled to 350 K before you can drink it.
S_A_V [24]

Answer:

The hot tea should transfer <em>25.63 kJ</em> the surroundings to cool the tea.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat has to be transferred from the tea to the surroundings to cool the tea (Q = ??? J).

m is the mass of the hot tea (m = dV = (1.0 g/mL)(250 mL) = 250 g), suppose the density of water is the density of tea.

c is the specific heat of the hot tea (c = 4.10 J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = final T - initial T = 350 K - 375 K = -25°C).

<em>∴ Q = m.c.ΔT</em> = (250 g)(4.10 J/°C.g)(-25°C)) = <em>- 25630 J = - 25.63 kJ.</em>

<em>So, the hot tea should transfer 25.63 kJ the surroundings to cool the tea.</em>

4 0
3 years ago
Consider the word equation. Calcium hydroxide hydrochloric acid mc012-1. Jpg calcium chloride water Which is the corresponding f
dimulka [17.4K]

The corresponding formula equation is:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

To obtain the word equation, we shall write out the balanced molecular equation. This is given below:

Calcium hydroxide => Ca(OH)₂

Hydrochloric => HCl

Calcium chloride => CaCl₂

Water => H₂O

Calcium hydroxide + Hydrochloric —> Calcium chloride + water

Ca(OH)₂ + HCl —> CaCl₂ + H₂O

There are 2 atoms of Cl on the right side and 1 atom on the left. It can be balance by writing 2 before HCl as shown below:

Ca(OH)₂ + 2HCl —> CaCl₂ + H₂O

There are a total of 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 2 before H₂O as shown below:

Ca(OH)₂ + 2HCl —> CaCl₂ + 2H₂O

Now, the equation is balanced.

Thus, the corresponding word equation is:

Upper Ca (upper OH) subscript 2 (s) plus 2 upper H upper Cl (l) right arrow upper Ca upper Cl subscript 2 (aq) plus 2 upper H subscript 2 upper O (l)

Learn more about balancing equation: brainly.com/question/15538713

8 0
2 years ago
Read 2 more answers
The formula for cocaine is C17H21N04. What is the percentage of carbon in the
PolarNik [594]
The correct answer is d
6 0
4 years ago
Read 2 more answers
Starch is a type of: Protein Fat Nucleic acid Sugar
Svetllana [295]

Answer:

it's not a protien at all

Explanation:

Starch is not a protein. Starch is a type of carbohydrate. It is a polysaccharide, it has lots of sugars though

8 0
3 years ago
In boyle's law, the initial volume of a gas is 120 ml at 256 kpa. what will be the volume if the pressure increases to 385 kpa?
Vinil7 [7]
<h3>Answer:</h3>

79.8 ml

<h3>Explanation:</h3>

Boyle's law describes the relationship between pressure and volume when the temperature is constant. For this question, I will be rounding to significant figures.

Boyle's Formula

When describing the relationship between pressure and volume, the formula \displaystyle P_{1} V_{1}= P_{2} V_{2}. In this formula, P_{1}V_{1} is the initial pressure and volume. On the other side, P_{2} V_{2} is final pressure and volume. So, to find a missing variable you must plug in the values you are given.

Final Volume

Remember when solving this question to remain constant in your units. When we plug in the values we know we are given:

  • 256kPa*120mL=385kPa*V_{2} mL

Now, we can multiply the left side

  • 30720kPa*mL=385kPa*V_{2} mL

Finally, we can divide by 385 to isolate the final volume

  • 79.8mL=V_{2}

This gives the final volume of 79.8mL.

7 0
2 years ago
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