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sergey [27]
2 years ago
5

What can the flow of electrons be easily compared to?

Chemistry
1 answer:
julsineya [31]2 years ago
7 0
I think B, the flow of water:))
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Someone help it’s due today
Kitty [74]

Answer:

All elements are neutral

Explanation:

The plum pudding model of the atom indicated that all elements are neutral. The model was proposed by J.J Thomson after he conducted his experiment on the gas discharge tube.

From the experiment he discovered electrons which he called cathode rays.

Therefore, he suggested the plum pudding model of the atom.

The model describes negatively charge sphere surrounded by positive charges to balance them.

6 0
3 years ago
Is it necessary to prepare sodium extract to detect nitrogen in urea ?​
Vilka [71]

Answer:

I think No

Explanation:

7 0
2 years ago
A change in color indicates that what has occurred?
Alex

Answer:

it's an indicator that a chemical reaction occurred.

6 0
3 years ago
“Fe(NO3)3” is a...
ioda

Answer:

1. Fe(NO3)3 is C. Chemical formula

2. Manganese Sulphate is C. Name

3. Zn is C. Symbol

Hope this helps!

3 0
3 years ago
How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?
Nina [5.8K]

11.48-gram of KCl0_3 are needed to produce 6.75 Liters of O_2  gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=298 K

Putting value in the given equation:

\frac{PV}{RT}=n

n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}

Moles = 0.3588 moles

Now,

Moles = \frac{mass}{molar \;mass}

0.3588 moles = \frac{mass}{32}

Mass= 11.48 gram

Hence, 11.48-gram of KCl0_3 are needed to produce 6.75 Liters of O_2 gas measured at 1.3 atm pressure and 298 K

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

3 0
2 years ago
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