Write an equation that is parallel to y = 3x + 5 and passes through the point (-4, -13)

Mathematics

1 answer:

larisa86 [58]3 years ago

5 0

Y equals three x minus one

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Simplify completely 10x6y3+20x3y2/5x3y

Kryger [21]

Answer:

$\large\boxed{\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=2x^3y^2+4y}$

Step-by-step explanation:

$\dfrac{10x^6y^3+20x^3y^2}{5x^3y}=\dfrac{(5x^3y)(2x^3y^2)+(5x^3y)(4y)}{5x^3y}\\\\=\dfrac{5x^3y(2x^3y^2+4y)}{5x^3y}\qquad\text{cancel}\ 5x^3y\\\\=2x^3y^2+4y$

8 0

3 years ago

Please help me solve!

Elina [12.6K]

Answer:

Step-by-step explanation:

Comment

There are a number of ways of doing this problem. I don't know which method you are intended to use. One sure way in this case is graphing the equation, I have done this for you. See below. The maximum volume occurs where x = 2

The graph shows that there is a peak at x = 2. That is where the maximum volume is,

Answer

x = 2