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Lunna [17]
3 years ago
7

Why do we call real solutions zeros?

Mathematics
2 answers:
Delvig [45]3 years ago
8 0

Answer:

Basically because they cross or touch the X axis which would be 0 on the x side. this means (0,1)... (0,8) etc

Minchanka [31]3 years ago
4 0

Answer:

Let's start by defining these terms. The roots of a polynomial are values of the variable that make the polynomial equal to zero. The solutions of an equation are values of the variable that make the equation true. ... The zeros of a function are the values of the input to the function that make the output equal to zero.

Step-by-step explanation:

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Which of the following inequalities matches the graph? (1 point)
Aleksandr [31]

Answer: 2x + y < 7

Step-by-step explanation:

In the graph we can see that:

The line is a dashed line, and the shaded area is below the dashed line, then we will have something like:

y < a*x + b

We also can see that the slope of the line is negative, and that the y-intercept is +7

Then the inequality will be something like:

y < a*x + 7

Now we can see that the line passes through the points (0, 7) and (3, 1)

Then the slope will be:

a = (1 - 7)/(3 - 0) = -6/3 = -2

that is negative, as we already said.

Then we have:

y < -2*x + 7

we can rewrite this as:

2x + y < 7

This is the first solution shown.

7 0
3 years ago
IF YOU GET ANSWR RIGHT YOU GET BRAINLIEST!
ollegr [7]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f
vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

f(x)=ax^3+bx^2+cx+d

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

y = x^3 - x

Equate y to 0

x^3 - x = 0

Expand

x(x^2 - 1) = 0

Express x^2 - 1 as difference of two squares

x(x - 1)(x +1 ) = 0

<em>x = 0 or 1 or -1</em>

For 2 x intercepts

y = x^3 - x

y  =(x-5)^2)(x+7)

Equate y to 0

(x-5)^2(x+7) = 0

Expand

(x-5)(x-5)(x+7) = 0

<em>x= 5 or x = -7</em>

For 1 x intercept

y = x^3

Equate y to 0

x^3 = 0

Take cube roots of both sides

x = 0

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

y = x^2 + x + 17

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

y = x^2- 6x + 9

Equate y to 0

x^2- 6x + 9 = 0

Expand

x^2 - 3x - 3x + 9 = 0

(x - 3)(x-3) = 0

x = 3

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0
3 years ago
PLEASE HELP WILL GET BRAINIEST
NeX [460]
You have a lot of questions here, I can help you with a few of them.

When you simplify the polynomials, you put together all of the terms that have the same degree. That means the variables have the same exponents. The number of terms are the items separated by plus and minus signs.

Here are the answers for the first three:


1) 8x^3+2x^2-3x+9&#10;

2)  4w^2 + 14w + 17

3)  -3x^3+9x^2 +3x
6 0
4 years ago
Read 2 more answers
Write four different expressions for the perimeter of a pentagon whose sides are all s-2 units long?
Masteriza [31]

Hey there!

1. 5(s-2) This is because s-2 is the length of each side, and there are 5 sides in a pentagon all of that length, so multiplying it by 5 like this shows its perimeter.

2. 5s-10 This can be found by distributing the first equation, multiplying both s and -2 by 5.

3. (s-2) + (s-2) + (s-2) + (s-2) + (s-2) Each grouping in the parenthesis represents each of the 5 sides, so adding them all together will get you the perimeter.

4. 5(s) + 5(-2) This one is most like the first one, except it's a little more spread out. Multiply the term s by the 5 sides in one grouping, and the integer -2 by 5 in the other.

Hope this helps!

4 0
3 years ago
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