Why do we call real solutions zeros?

Mathematics

2 answers:

Delvig [45]2 years ago

8 0

Answer:

Basically because they cross or touch the X axis which would be 0 on the x side. this means (0,1)... (0,8) etc

Minchanka [31]2 years ago

4 0

Answer:

Let's start by defining these terms. The roots of a polynomial are values of the variable that make the polynomial equal to zero. The solutions of an equation are values of the variable that make the equation true. ... The zeros of a function are the values of the input to the function that make the output equal to zero.

Step-by-step explanation:

You might be interested in

If X= 4 solve this equation: <br><br><br> 2x + 3=

nlexa [21]

Answer:

Step-by-step explanation:

2x + 3

2(4) + 3 .......................replace x with 4

8 + 3

4 0

2 years ago

Read 2 more answers

PLEASE HELP 8th GRADE MATH QUESTION OVER HERE!!!

patriot [66]

The side AB measures option 2. $\sqrt{20}}$ units long.

Step-by-step explanation:

Step 1:

The coordinates of the given triangle ABC are A (4, 5), B (2, 1), and C (4, 1).

The sides of the triangle are AB, BC, and CA. We need to determine the length of AB.

To calculate the distance between two points, we use the formula $d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}.$

where ( $x_{1},y_{1}$ ) are the coordinates of the first point and ( $x_{2},y_{2}$ ) are the coordinates of the second point.

Step 2:

For A (4, 5) and B (2, 1), ( $x_{1},y_{1}$ ) = (4, 5) and ( $x_{2},y_{2}$ ) = (2, 1). Substituting these values in the distance formula, we get

$d=\sqrt{\left(2-4\right)^{2}+\left(1-5}\right)^{2}} = \sqrt{\left(2\right)^{2}+\left(4}\right)^{2}}=\sqrt{20}}.$