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IgorLugansk [536]
3 years ago
14

Name four products of incomplete combustion 1 - ____ 2 -____ 3 -____ 4 -_____

Chemistry
1 answer:
faltersainse [42]3 years ago
3 0

Answer:

Carbon Monoxide / Carbon Dioxide / Sulfur  and Nitrogen Dioxide

Explanation:

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Calculate the percent yield when 500 grams of carbon dioxide react with an excess of water to produce 640 grams of carbonic acid
Elena-2011 [213]

Answer:

Percent yield =  90.5%

Explanation:

Given data:

Mass of carbon dioxide = 500 g

Mass of water = excess

Actual yield of carbonic acid = 640 g

Percent yield = ?

Solution:

Balanced chemical equation:

CO₂ + H₂O  → H₂CO₃

Number of moles of carbon dioxide

Number of moles  = Mass / molar mass

Number of moles = 500 g/ 44 g/mol

Number of moles = 11.4 mol

Now we will compare the moles of H₂CO₃ with CO₂.

                              CO₂          :              H₂CO₃

                                 1             :                  1

                               11.4           :                11.4

Mass of carbonic acid:

Mass = number of moles × molar mass

Mass = 11.4 mol × 62.03 g/mol

Mass = 707.14 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield =  640 g/ 707.14 g × 100

Percent yield =  90.5%

7 0
3 years ago
Quick help I really need help
Sauron [17]

Answer:

CO2 H2o

Explanation:

8 0
3 years ago
Which of the following symbolic representations of matter signifies a mixture of elements?
andreev551 [17]
D only..

A is pure compound
B is mixture of compound and element
C is mixture of compounds
D is mixture of elements
7 0
3 years ago
Write the chemical equations for the neutralization reactions that occurred when hcl and naoh were added to the buffer solution.
irga5000 [103]
A base and an Acid always react to form a salt and water

So, HCl + NaOH —> NaCl + HOH
5 0
3 years ago
A sample of gas at a pressure of 121.59 kPa, a volume of 31 L, and a temperature of 360 K contains how many moles of gas? A. 0.7
natali 33 [55]

Answer:

C. 1.3 mol

Explanation:

PV = nRT

where P is absolute pressure,

V is volume,

n is number of moles,

R is universal gas constant,

and T is absolute temperature.

Given:

P = 121.59 kPa

V = 31 L

T = 360 K

R = 8.3145 L kPa / mol / K

Find: n

n = PV / (RT)

n = (121.59 kPa × 31 L) / (8.3145 L kPa / mol / K × 360 K)

n = (3769.29 L kPa) / (2993.22 L kPa / mol)

n = 1.26 mol

Round to two significant figures, there are 1.3 moles of gas.

4 0
3 years ago
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