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sattari [20]
2 years ago
9

Chemical bonding in metals is

Chemistry
1 answer:
777dan777 [17]2 years ago
8 0

Answer:

different from ionic or covalent bonding

Explanation:

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PLS HELP THIS IS ACTUALLY SCIENCE
Alekssandra [29.7K]

Answer:

Death rates, Birth rates, and immigration rates

Explanation:

5 0
3 years ago
Read 2 more answers
Matching
kotegsom [21]

Answer:

a mixture of molecules - Box f

atoms of a pure elementa metal - Box D

a solid compound - Box C

a mixture of elements - Box A

Explanation:

Box a has mixture of elements which forms a solid like shape but there are different elements present in the box. The box f has mixture of molecules in which many atoms are combined together. Box c has solid compound with single element.

5 0
3 years ago
At 1.00 atmosphere pressure, a certain mass of a gas has a temperature of 100oC. What will be the temperature at 1.13 atmosphere
Inessa [10]

Answer:  Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

{P_1\times T_1}={P_2\times T_2}

where,

P_1 = initial pressure of gas   = 1.00 atm

P_2 = final pressure of gas  = 1.13 atm

T_1 = initial temperature of gas  = 100^0C=(100+273)K=373K K

T_2 = final temperature of gas  = ?

{1.00\times 373}={1.13\times T_2}

T_2=330K

Therefore, the final temperature of the gas will be 330 K.

7 0
3 years ago
Which relationship or statement best describes delta s for the following reaction:
zalisa [80]

Answer:

b) Delta S < 0

Explanation:

The change in the entropy (ΔS) is related to the change in the number of gaseous moles of the reaction: Δn(g) = n(g, products) - n(g, reactants).

  • If Δn(g) > 0, the entropy increases (ΔS > 0).
  • If Δn(g) < 0, the entropy decreases (ΔS < 0).
  • If Δn(g) = 0, there is little or no change in the entropy

Let's consider the following equation.

2 H₂S(g) + 3 O₂(g) → 2 H₂O(g)

Δn(g) = 2 - 5 = - 3. Since Δn(g) < 0, the entropy decreases and ΔS < 0.

4 0
3 years ago
When 0.313 g of Mg is heated strongly in a nitrogen (N2) atmosphere, a chemical reaction occurs. The product of the reaction wei
borishaifa [10]

Answer:

Mg₃N₂ (magnesium nitride)

Explanation:

M(total) = M(mg) + M (n)

M (n) = M(total) -  M(mg)

        = 0.433g - 0.313g

        = 0.12g

mole (N) =  0.12g / 14.0067 g/mol

              = 0.008567

mole Mg = 0.313g / 24.3050 g/mol

              = 0.012878

Mg = 0.012878 / 0.008567

     = 1.5

N = 0.008567 / 0.008567

   = 1

multiply by 2 to get whole numbers

Mg = 1.5 × 2 = 3

N = 1  × 2 = 2

Mg₃N₂ (magnesium nitride)

8 0
3 years ago
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