All categories

3 years ago

This circle is centered at the orgin, and the length of it’s radius is 5. What is the ewuation of the circle?

Mathematics

2 answers:

pav-90 [236]3 years ago

8 0

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{0}{ h},\stackrel{0}{ k})\qquad \qquad 
radius=\stackrel{5}{ r}
\\\\\\
(x-0)^2+(y-0)^2=5^2\implies x^2+y^2=25$

Eva8 [605]3 years ago

4 0

Answer:

The answer is D. x^2 + y^2=5^2 (APEX)

Step-by-step explanation:

You might be interested in

at memorial hospital 9 of the 12 babies born on Tuesday were boys In simplest form What fraction of the babies born on Tuesday w

Papessa [141]

9/12 = (9/3) / (12/3)= 3/4.

3/4 of the babies born on Tuesday were boys~

5 0

3 years ago

Read 2 more answers

Two fractions with different denominators that have the sum of 1/3

klemol [59]

1/4. and. 1/12. will do that.

3 0

3 years ago

Find the distance between A and B

harina [27]

Answer:

The distance between A and B is 2.6

Step-by-step explanation:

We know that there are 2 whole numbers from -1 to 0 and 0 to 1. Then we can add the 0.3 from both sides. 0.3 plus 0.3 is 0.6.

I hope this helped and if it did I would appreciate it if you marked me brainliest, thank you and have a nice

day

8 0

3 years ago

Read 2 more answers

An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2000 individ

Tema [17]

Answer:

a) P=0.558

b) P=0.021

Step-by-step explanation:

We can model this random variable as a Poisson distribution with parameter λ=1/500*2000=4.

The approximate distribution of the number who carry this gene in a sample of 2000 individuals is:

$P(x=k)=\frac{\lambda^ke^{-\lambda}}{k!} =\frac{4^ke^{-4}}{k!}$

a) We can calculate that the approximate probability that between 4 and 9 (inclusive) as:

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)\\\\\\ P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\P(9)=4^{9} \cdot e^{-4}/9!=262144*0.0183/362880=0.013\\\\\\$

$P(4\leq x\leq 9)=\sum_{k=4}^9P(k)=0.195+0.156+0.104+0.060+0.030+0.013=0.558$

b) The approximate probability that at least 9 carry the gene is:

$P(x\geq9)=1-P(x\leq 8)\\\\\\$

$P(0)=4^{0} \cdot e^{-4}/0!=1*0.0183/1=0.018\\\\P(1)=4^{1} \cdot e^{-4}/1!=4*0.0183/1=0.073\\\\P(2)=4^{2} \cdot e^{-4}/2!=16*0.0183/2=0.147\\\\P(3)=4^{3} \cdot e^{-4}/3!=64*0.0183/6=0.195\\\\P(4)=4^{4} \cdot e^{-4}/4!=256*0.0183/24=0.195\\\\P(5)=4^{5} \cdot e^{-4}/5!=1024*0.0183/120=0.156\\\\P(6)=4^{6} \cdot e^{-4}/6!=4096*0.0183/720=0.104\\\\P(7)=4^{7} \cdot e^{-4}/7!=16384*0.0183/5040=0.06\\\\P(8)=4^{8} \cdot e^{-4}/8!=65536*0.0183/40320=0.03\\\\$

$P(x\geq9)=1-P(x\leq 8)\\\\P(x\geq9)=1-(0.018+0.073+0.147+0.195+0.195+0.156+0.104+0.060+0.030)\\\\P(x\geq9)=1-0.979=0.021$

8 0

3 years ago

PLZ HELP ASAP WILL GET BRAINLIEST WHEN IT LETS ME

solniwko [45]

That part is the median, which is 57.

7 0

3 years ago

Read 2 more answers