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3 years ago

5

A circle has a diameter of 28 units What is the area of the circle to the nearest hundredth

1 answer:

OverLord2011 [107]3 years ago

6 0

28/2=14
14=radius

Area=3.14*14*14
=615.44

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What is the rate of change between (-8,- 8) and (0,8)

iren [92.7K]

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

We need to find thr rate of change (slope) of the line joining these two points ~

$\qquad \sf \dashrightarrow \: m = \dfrac{rise}{run}$

$\qquad \sf \dashrightarrow \: m = \cfrac{8 - ( - 8)}{0 - ( - 8)}$

$\qquad \sf \dashrightarrow \: m = \cfrac{8 + 8}{0 + 8}$

$\qquad \sf \dashrightarrow \: m = \cfrac{16}{8}$

$\qquad \sf \dashrightarrow \: m = 2$

Slope of the line (m) joining the two points is 2 ~

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2 years ago

Find x, round to the nearest tenth degree.

Romashka [77]

Answer:

Step-by-step explanation:

Use the Law of Cosines

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3 years ago

Levi's school is at the corner of the high streetand second avenue. The corner forms a right angle. How ight he describe the way

Varvara68 [4.7K]

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he can bring phone to school and show route in Google map

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3 years ago

Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

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3 years ago

F(x)=2x^2 -5 , simplify f(x+h)/h , where h≠0

7nadin3 [17]

Answer:

$\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}$

$\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}$

Step-by-step explanation:

$f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0$

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2 years ago