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Margarita [4]
3 years ago
9

35.0 mL of 12.0 M HCl is added to enough water to have a final volume of 1.20 L. What is the molarity of the final solution?

Chemistry
1 answer:
creativ13 [48]3 years ago
6 0
<h3>Answer:</h3>

0.35 M

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial volume as 35.0 mL or 0.035 L
  • Initial molarity as 12.0 M
  • Final volume is 1.20 L

We are required to determine the final molarity of the solution;

  • Dilution involves adding solvent to a solution to make it more dilute which reduces the concentration and increases the solvent while maintaining solute constant.
  • Using dilution formula we can determine the final molarity.

M1V1 = M2V2

  • Rearranging the formula;

M2 = M1V1 ÷ V2

     = (12.0 M × 0.035 L) ÷ 1.2 L

      = 0.35 M

Thus, the final concentration of the solution is 0.35 M

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A sample of oxygen gas in one container has a volume of 20.0mililiter at 297 K and 101.3 kPa. The entire sample is transferred t
VashaNatasha [74]

Answer: V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1T_2}{T_1P_2}

where,

P_1 = initial pressure of gas = 101.3 kPa

P_2 = final pressure of gas = 94.6 kPa

V_1 = initial volume of gas = 20.0 ml

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 297K

T_2 = final temperature of gas = 283K

Now put all the given values in the above equation, we get the final volume of gas.

V_2=\frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

V_2=20.4ml

Thus the correct numerical setup for calculating the new volume is \frac{101.3kPa\times 20.0ml\times 283K}{297K\times 94.6kPa}

3 0
3 years ago
How many moles are present in 1.75 g of zinc sulfate, Znso, ?
Cerrena [4.2K]

Explanation:

We assume you are converting between grams ZnSO4 and mole. You can view more details on each measurement unit: molecular weight of ZnSO4 or mol This compound is also known as Zinc Sulfate. The SI base unit for amount of substance is the mole. 1 grams ZnSO4 is equal to 0.0061941519772353 mole.

7 0
3 years ago
Commercial grade HCl solutions are typically 39.0% (by mass) HCl in water. Determine the molality of the HCl, if the solution ha
marta [7]

Molality of the solution is defined as the number of moles of a substance dissolved divided by the mass of the solvent:

Molality = number of moles / solvent mass

From the concentration of 39% (by mass) of HCl in water, we construct the following  reasoning:

in 100 g solution we have 39 g hydrochloric acid (HCl)

number of moles  = mass / molecular weight

number of moles of HCl = 39 / 36.5 = 1.07 moles

solvent (water) mass = solution mass - hydrochloric acid mass

solvent (water) mass = 100 - 39 = 61 g

Now we can determine the molality:

molality = 1.07 moles / 61 g = 0.018

8 0
3 years ago
HELP PLSSSS
den301095 [7]

Answer:

Groups like the Halogens, which include Chlorine and Flourine, share similar properties both behaviorally and structurally. The Periodic Table is essentially a bunch of patterns and trends and the groups (like the one with Sodium and Potassium) were grouped together because of these similarities.

Explanation:

https://en.wikipedia.org/wiki/Alkali_metal

8 0
2 years ago
What type of large molecule is responsible for repair and growth of cells?
Oliga [24]

Answer:

The answer is a. proteins

7 0
3 years ago
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