The equation 2al(s) + 3br2(l) → 2albr3(s) is a(n) _____________

A sample of oxygen gas has a volume of 150.0 ml when its pressure is .947 atm. what will the volume of the gas be if the tempera

joja [24]

D
Hope it helped you get an A, Kayla.

7 0

2 years ago

What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according

ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

Step 1: The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

Step 2: Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

Step 3: Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

Step 4: Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0

2 years ago

An iron bar of mass 841 g cools from 84°C to 7°C. Calculate the heat released (in kilojoules) by the metal.

Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

Final temperature = 7°C

Heat released = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 7°C - 84°C

ΔT = -77°C

By putting values,

Q = 841 g × 0.444 j/g.°C × -77°C

Q = 28752.11 j

In Kj:

28752.11 j × 1 kJ / 1000 J

28.75211 kj

8 0

2 years ago

List any two uses of Brass , Bronze , Sulphur , Iodine

NikAS [45]

BRASS :It is easy to form into various shapes, a good conductor of heat, and generally resistant to corrosion from salt water. 1 pipes and 2 tubes, 3 screws, 4 cartridge casings for firearms.

BRONZE :for bearings because of its friction properties, and as 1 musical instruments ,2 and medals

Sulphur :1 making car batteries, 2 fertilizer

IODINE :1 Iodine regulates skin moisture levels and aids in the healing of cuts and scars through cellular regeneration. 2 Iodine also regulates the hormones responsible for acne breakouts.3 Treating thyroid cancer.

5 0

2 years ago

Most carbon based molecules are classified as

kherson [118]

the answer is organic molecule

7 0

2 years ago

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The equation 2al(s) + 3br2(l) → 2albr3(s) is a(n) ______________ reaction.