Which describes the process that forms teflon tm? molecular fluorine (f2) undergoes polymerization. a fluorocarbon polymer break
s apart into monomers. tetrafluoroethene (cf2cf2) undergoes polymerization. 1,1,2,2-tetrafluoroethane (chf2chf2) undergoes polymerization?
2 answers:
Answer:
T<span>etrafluoroethene (F</span>₂CCF₂<span>) undergoes polymerization describes the formation of Teflon.
Explanation:
Polymerization is the process in which small units called as monomers join together repeatedly and forms a long chain macro-molecule called as polymer.
In given question the monomer is Tetrafluoroethene because alkenes can undergo polymerization via Addition polymerization via following mechanism.
a) Free Radical Addition Reaction
b) Acid Catalyzed Addition Reaction
c) Base catalyzed Addition Reaction
The formation of Teflon from Tetrafluoroethene is shown below,</span>
T<span>etrafluoroethene (F</span>₂CCF₂<span>) undergoes polymerization describes the formation of Teflon.
Explanation:
Polymerization is the process in which small units called as monomers join together repeatedly and forms a long chain macro-molecule called as polymer.
In given question the monomer is Tetrafluoroethene because alkenes can undergo polymerization via Addition polymerization via following mechanism.
a) Free Radical Addition Reaction
b) Acid Catalyzed Addition Reaction
c) Base catalyzed Addition Reaction
The formation of Teflon from Tetrafluoroethene is shown below,</span>
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Answer : The fraction of carbonic acid present in the blood is 5.95%
Explanation :
The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.
The pH of a buffer is calculated using Henderson equation which is given below.
We have been given,
pH = 7.5
pKa of carbonic acid = 6.3
Let us plug in the values in Henderson equation to find the ratio Base/Acid.
The total of mole fraction of acid and base is 1. Therefore we have,
But Base = 15.8 x [Acid]. Let us plug in this value in above equation.
[Acid] = 0.0595 x 100 = 5.95 %
The fraction of carbonic acid present in the blood is 5.95%