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Lynna [10]
3 years ago
6

Which describes the process that forms teflon tm? molecular fluorine (f2) undergoes polymerization. a fluorocarbon polymer break

s apart into monomers. tetrafluoroethene (cf2cf2) undergoes polymerization. 1,1,2,2-tetrafluoroethane (chf2chf2) undergoes polymerization?

Chemistry
2 answers:
Stella [2.4K]3 years ago
6 0
Answer:
             T<span>etrafluoroethene (F</span>₂CCF₂<span>) undergoes polymerization describes the formation of Teflon.

Explanation:
                    Polymerization is the process in which small units called as monomers join together repeatedly and forms a long chain macro-molecule called as polymer.
                    In given question the monomer is Tetrafluoroethene because alkenes can undergo polymerization via Addition polymerization via following mechanism.
                            a)  Free Radical Addition Reaction

                            b)  Acid Catalyzed Addition Reaction

                            c)  Base catalyzed Addition Reaction

The formation of Teflon from Tetrafluoroethene is shown below,</span>

Flauer [41]3 years ago
4 0

Answer: tetrafluoroethene(CF2CF2) undergoes polymerization

Explanation:

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A sample of SO2 gas occupies 45.6 L at 373 K and 3.45 atm. This sample contains how many moles of oxygen atoms?
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Answer:

10.28 mol

Explanation:

S + 2O = SO2

(atm x L) ÷ (0.0821 x K)

(3.45 x 45.6) ÷ (0.0821 x 373)

=5.13726

Then round it to significant figures

=5.14

5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)

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Colorimetric methods of analysis are based on having a reagent that changes _____________ as a function of the concentration of
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Colorimetric methods of analysis make use of Color changes in reagents to decipher the concentration of solutions.

Therefore, color completes the sentence

<h3>Colourimetric analysis</h3>

Generally, Colorimetric analysis is used to know the concentration of a chemical element in a solution while using colour indicators or reagents.

Therefore

Colorimetric methods of analysis are based on having a reagent that changes Color as a function of the concentration of the analyte.

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1 year ago
Calculate the pOH of an aqueous solution of .0.073 M LiOH
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Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

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Replacing in the definition of pOH:

pOH= -log (0.073 M)

<u><em>pOH= 1.14 </em></u>

In summary, the pOH of the aqueous solution is 1.14

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