Explanation:
It is known that molality is the number of moles present in kg of solution.
Mathematically, Molality = 
The given data is as follows.
Molar mass of ammonia = 17 g/mol
Concentration = 1.002 mg/L = 
= 
mol/L
Also, density = 
= 1 kg/L
Therefore, molality will be calculated as follows.
Molality = 
= 
And,
Molar mass of nitrite = 46 g/mol
Concentration = 0.387 mg/L = 
= 
mol/L
And, density = = 1 kg/L
Hence, molality = 
= mol/kg
Now, Molar mass of nitarte = 62 g/mol
Concentration = 1352.2 mg/L
= 
= 0.02181 mol/L
Also, density = = 1 kg/L
Hence, molality will be calculated as follows.
Molality = 
= 0.02181 mol/kg
Therefore, molality of given species is for ammonia, mol/kg for nitrite, and 0.02181 mol/kg for nitrate ion.
Answer:
HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)
Explanation:
From the question given above
HNO₃ + H₂O —> ?
Nitric acid, HNO₃ reacts with water, H₂O to form aqueous solution of nitric acid as illustrated below:
HNO₃ + H₂O —> HNO₃ (aq)
Nitric acid is a strong acid and, so will ionised completely when dissolved in water. This is illustrated below:
HNO₃ (aq) —> H⁺ (aq) + NO₃¯ (aq)
Answer:
According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs. Hence, the correct statement is arrhenius acid produces hydrogen ions in solution.
Answer:
The first condition is that ocean waters must be above 26 degrees Celsius (79 degrees Fahrenheit). Below this threshold temperature, hurricanes will not form or will weaken rapidly once they move over water below this threshold.
Answer:
1.) 13 g C₄H₁₀
2.) 41 g CO₂
Explanation:
To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O
48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 13 g C₄H₁₀
48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 41 g CO₂
