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Vesnalui [34]
3 years ago
12

A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el

ectrical potential energy of the particle?
(1)1.07 × 10 19eV
(2)2.16 × 10 18eV
(3)1.50 eV
(4)13.5 eV
Physics
1 answer:
ollegr [7]3 years ago
8 0
The answer:
the relationship between elementary charge, potential difference and electrical potential energy is given by 
   E= qV
E:  lectrical potential energy
q:   elementary charge
V:   potential difference

but we have  e=abs val(q)=3 
so we have E= qV=3ex4.5V=<span>13.5 eV
</span>
the answer is <span>(4)13.5 eV</span>

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Answer:

<em>J=36221 Kg.m/s</em>

Explanation:

<u>Impulse-Momentum Theorem</u>

These two magnitudes are related in the following way. Suppose an object is moving at a certain speed v_1 and changes it to v_2. The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by

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The magnitude of J is

J=36221 Kg.m/s

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