Question

A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in electrical potential energy of the particle?
(1)1.07 × 10 19eV
(2)2.16 × 10 18eV
(3)1.50 eV
(4)13.5 eV

Answer 1

The answer:
the relationship between elementary charge, potential difference and electrical potential energy is given by 
   E= qV
E:  lectrical potential energy
q:   elementary charge
V:   potential difference

but we have  e=abs val(q)=3 
so we have E= qV=3ex4.5V=13.5 eV

the answer is (4)13.5 eV