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2 years ago

An unstoppable object is heading right toward an unmovable object. What's going to happen?

Physics

1 answer:

marshall27 [118]2 years ago

8 0

Answer:

In my opinion the unstoppable object will hit the unmovable object and stop but the wheels will still be rolling and trying to move but can't.

<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

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A very long insulating cylinder of charge of radius 2.50 cm carries a uniform linear density of 15.0 nC/m. (

Pavlova-9 [17]

Answer:

r2 = 2.401557 cm

distance = 0.10 cm

Explanation:

given data

radius = 2.50 cm

density = 15.0 nC/m

voltmeter read = 175

solution

we know here potential difference that is express as

ΔV = $\frac{\lambda }{2\pi \epsilon _o} ln\frac{r2}{r1}$ ...........1

so here

$ln\frac{r2}{r1} = 2\pi \epsilon _o \times \frac{\triangle V}{\lambda }$

as here $\lambda$ is linear charge density

$\frac{r2}{r1} = e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}$

r2 = r1 × $e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}$

r2 = 2.40 × $e^{2\pi 8.85\times 10^{-12} \times \frac{175}{15\times 10^{-6} }}$

r2 = 2.401557 cm

and

here distance above surface will be

distance = r1 - r2

distance = 2.50 - 2.40

distance = 0.10 cm

4 0

3 years ago

Please help me with these I might need more than only 1 person to answer

Sindrei [870]

Explanation:

a) copper

b) olive oil

Hope it helps✌✌

7 0

3 years ago

Jennifer is making a collage using her favorite photos. She wants to cover the collage with something that allows her to see the

Karolina [17]

B.) A transparent material

4 0

3 years ago

Read 2 more answers

The electric field between the plates of a parallel-plate capacitor is horizontal, uniform, and has a magnitude E. Asmall object

kirza4 [7]

Answer:

$m = 0.041 kg$

Explanation:

As we know that the small particle is in equilibrium at an angle of 16 degree with the vertical

so here we can use force balance in vertical and horizontal direction

$T cos\theta = mg$

$T sin\theta = qE$

now from above equation we have

$T = \sqrt{(mg)^2 + (qE)^2}$

also by division of above two equations we have

$\frac{qE}{mg} = tan\theta$

$qE = mg tan\theta$

now from above equation again

$T = \sqrt{(mg)^2 + (mg)^2 tan^2\theta}$

$T = mg sec\theta$

$0.420 = m(9.81) sec 16$

$m = 0.041 kg$

3 0

3 years ago

Tiana jogs 1.5 km along a straight path and then turns and jogs 2.4 km in the opposite direction. She then turns back and jogs 0

vichka [17]

Answer:

Distance: 4.6km Displacement= -0.2km

Explanation:

Total distance: 1.5+2.4+0.7= 4.6 km

Displacement: 1.5-2.4+0.7= -0.2km

The displacement may also be 0.2km, it just depends on if it wants it negative or not.

7 0

3 years ago