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Wittaler [7]
4 years ago
11

A whale comes to the surface to breathe and then dives at an angle of 20.0 ∘ below the horizontal. If the whale continues in a s

traight line for 200 m , how deep is it?
Physics
2 answers:
charle [14.2K]4 years ago
8 0

Answer:

It is 68.404 m deep.

Explanation:

The motion of the whale can be seen in the form of a right-angle triangle.

Angle of deviation = 20°

We know that, sinФ = Perpendicular/ Hypotenuse.

Here, hypotenuse = 200 m

Depth is perpendicular that we have to find.

sin(20°) = Depth/200

Depth = sin(20°) * 200 = 68.404 meters.

-Dominant- [34]4 years ago
5 0

<u>Answer:</u>

<em>The depth is 68.4 meters. </em>

<u>Explanation:</u>

In this question the whale rose to the surface of the ocean to breath and then dives into the ocean at an angle of 20° below the horizontal line. It then travels 200 m straight along this line. We have to determine the <em>depth of the ocean. </em>

The path of the whale forms the <em>hypotenuse of a right triangle</em> and the angle between the hypotenuse and base is given as 20°.  Determination of sides or angles in a right triangle can be determines using trigonometry.  

<em>sinθ = \frac{(opposite \ side)}{hypotenuse} </em>

<em>opposite side = sinθ\times hypotenuse</em>

<em>Here θ = 20°  </em>

<em>sinθ = sin(20°) = 0.342 </em>

<em>opposite side= 0.342 \times 200 = 68.4 m  </em>

<em>Hence the depth is 68.4 m. </em>

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a) Minimum speed of the proton: 6.05\cdot 10^6 m/s

b) Angle of the velocity: \theta=-5.1^{\circ}

Explanation:

a)

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where v_0 is the initial speed. This equation can be rewritten as

t=\frac{x(t)}{v_0}

And substituting into the eq. for y,

y(t) = \frac{1}{2}\frac{qE}{m} \frac{x^2}{v_0^2}

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Therefore, we find the initial speed:

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b)

In order to find the angle, we just need to analyze the horizontal and vertical component of the final velocity of the proton.

The horizontal velocity is constant so it is:

v_x = v_0 = 6.05\cdot 10^6 m/s

The vertical velocity is given by:

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Solving for v_y,

v_y = \sqrt{2ay}=\sqrt{2\frac{qEy}{m}}=5.4\cdot 10^5 m/s

Therefore, the final angle of the velocity with respect to the horizontal is:

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And since the electric field is downward (the proton just misses the lower field), it means that the angle is below the horizontal:

\theta=-5.1^{\circ}

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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