Answer:
0.319 m³/s
Step-by-step explanation:
Data provided:
Initial volume in the river = 255 m³
Final volume required in the storage = 325 m³
Average outflow = 0.30 m³/s
Duration for raising the level = 1 hour = 3600 seconds
Now,
The actual volume required to raise the volume to 325 m³
= Final volume - Initial volume
= 325 m³ - 255 m³
= 70 m³
also,
the amount of outflow in 1 hour = Average rate of outflow × Time
= 0.30 m³/s × 3600 s
= 1080 m³
Therefore,
the total volume required = 1080 m³ + 70 m³ = 1150 m³
Now,
the average rate of inflow required = 
= 
= 0.319 m³/s
Answer:
a=possible amount
3a+28>200
Step-by-step explanation:
Answer:
Answer is (d) 3
You can see that :
6/2 = 12/4 = 18/6 = 24/8 = 30/10 = 3
Thua the answer is 3
Answer:
The correct option is;
Use a scale factor of 2
Step-by-step explanation:
The parameters given are;
A = (1, -6)
B = (5, -6)
C = (6, -2)
D = (0, -2)
A'' = (1.5, 4)
B'' = (3.5, 4)
C'' = (4, 2)
D'' = ( 1, 2)
We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4
The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2
Which gives;
AB/A''B'' = 4/2 = 2
Similarly;
The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17
The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2
Also we have;
The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6
The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3
For the side DA and D''A'', we have;
The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17
The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2
Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2
The correct option is therefore;
Use a scale factor of 2.
Answer:
SA=571.77
Step-by-step explanation:
SA==2πrh+2πr2=2·π·7·6+2·π·72≈571.76986
pls mark brainliest
