Answer:
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Consider the set S={1,2,3,4,5,6,7,8,9,12,13,14,15,16,17,18,19,23,24, .............. ,123456789}, which consists of all positive
jarptica [38.1K]
Answer:
12345
Step-by-step explanation:
The number of numbers with n digits is the same as the number of combinations of n things taken from 9. That means as many numbers have 5 or more digits as have 4 or fewer, with the exception that the number 123456789 is not matched by the number 0 (or a number with no digits). There are 256 numbers with 5 or more digits, but only 255 with 4 or fewer.
So, the median number is the first number with 5 digits:
12345
Answer:
3/50
Step-by-step explanation:
It's not as hard as you might think! You can just multiply the denominator and numerators separately. So in this case, you just need to do 9*1 and 25*6. This means that the answer is just 9/150, simplify it and you get, 3/50!
Answer:
Step-by-step explanation:
6 in to 13 ft = 9 in to x ft
6 / 13 = 9 / x.....cross multiply because this is a proportion
(6)(x) = (13)(9)
6x = 117
x = 117/6
x = 19.5 (or 19 1/2) ft <====
Answer:
Step-by-step explanation:
Volume of tank is 3000L.
Mass of salt is 15kg
Input rate of water is 30L/min
dV/dt=30L/min
Let y(t) be the amount of salt at any time
Then,
dy/dt = input rate - output rate.
The input rate is zero since only water is added and not salt solution
Now, output rate.
Concentrate on of the salt in the tank at any time (t) is given as
Since it holds initially holds 3000L of brine then the mass to volume rate is y(t)/3000
dy/dt= dV/dt × dM/dV
dy/dt=30×y/3000
dy/dt=y/100
Applying variable separation to solve the ODE
1/y dy=0.01dt
Integrate both side
∫ 1/y dy = ∫ 0.01dt
In(y)= 0.01t + A, .A is constant
Take exponential of both side
y=exp(0.01t+A)
y=exp(0.01t)exp(A)
exp(A) is another constant let say C
y(t)=Cexp(0.01t)
The initial condition given
At t=0 y=15kg
15=Cexp(0)
Therefore, C=15
Then, the solution becomes
y(t) = 15exp(0.01t)
At any time that is the mass.
