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3 years ago

What number of electrons balances the charges in this half reaction

Chemistry

1 answer:

Digiron [165]3 years ago

6 0

Answer : Two electrons balances the charges in this half reaction.

Explanation :

The given half reaction is,

$SO_2+2H_2O\rightarrow SO^{2-}_4+4H^+$

In this half reaction, there is no charges present on the left side of the reaction but on right side of the reaction, (2+) charge is present. So, two electrons (2-) are added on the right side of the reaction for balances the charge of the half reaction.

The balanced half reaction is,

$SO_2+2H_2O\rightarrow SO^{2-}_4+4H^++2e^-$

Hence, two electrons balances the charges in this half reaction.

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For each ionic compound formula, identify the main group to which X belongs: (c) X2SO4.

Zinaida [17]

The answer is group 1A.

In the ionic compound formula X₂SO₄, SO₄ has a -2 charge. Hence to balance this -2 charge of SO₄, X must have a +1 charge.

Group 1A elements form X⁺ type of ions because they are metals. So, they have the tendency to lose electrons.

Hence, X must belong to the 1A group.

Ionic Compounds-

Ionic compounds are formed by the electrostatic attraction between the anions and the cations.
Cations are positively charged ions that are formed due to the loss of electrons.
And the anions are negatively charged ions that are formed due to the gain of electrons.
Due to this, they have opposite charges and form bonds known as Ionic Bond.

To learn more about Ionic compounds, visit: brainly.com/question/9167977

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1 year ago

What is the hybridization of sb in the molecule sbcl52–? antimony (sb) can accept up to twelve electrons?

Setler79 [48]

The valence electron configuration for antimony (Sb) is:

Sb = 5s²5p³5d⁰

In SbCl₅²⁻, antimony has a -2 charge i.e. it has 2 additional electrons

Sb²⁻ = 5s²5p⁵5d⁰

Following a two electron transition from p→d orbital we have:

Sb²⁻ = 5s²5p³5d²

There is a total of 5 unpaired electrons (3 in the p and 2 in the d) which can form five bonds with the 5 Cl atoms.

Thus the hybridisation of Sb in SbCl₅²⁻ is sp³d²

5 0

3 years ago

Read 2 more answers

Consider the relationship (y+3)2 = b/(x-2), where y and x are variables and bis a constant. On rectangular coordinate paper, wha

Nikolay [14]

Answer:

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

Explanation:

$\frac{(y+3)}{2} = \frac{b}{(x-2)}$

Taking natural logarithm on both the sides:

$\ln [(y+3)]-\ln[2]=\ln [b]-\ln [(x-2)]$

$\ln [(y+3)]=\ln[2]+\ln [b]-\ln [(x-2)]$

$\ln [(y+3)]=\ln {[2\times b]-\ln [(x-2)]$

Slope intercept form is generally given as:

$y=mx+c$

m = slope, c = intercept on y axis or vertical axis

On rearranging equation:

$\ln [(y+3)]=(-1)\times \ln [(x-2)]+\ln {2b}$

y = ln [(y+3)], x = ln [(x-2)], m=-1 , c = ln 2b

(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

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3 years ago

In the "Design a Thermos" lab, the temperature of the thermos was compared with a container that was not insulated.

Hitman42 [59]

Answer:

Explanation:

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Classify each salt as acidic, basic, or neutral? -nh4cl -ca(no32

vichka [17]

The pH of salt depends on the component acid and base that comprise them. For example, if the salt is made up of strong acid and weak base then, the salt is acidic. If the salt is formed from strong base and weak acid then, the salt is basic. For this item, NH4Cl is acidic and also Ca(NO3)2 is acidic.

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2 years ago