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laila [671]
4 years ago
14

Calculate the grams of calcium present in 70 grams of calcium chloride.

Chemistry
1 answer:
Dmitry_Shevchenko [17]4 years ago
4 0

Answer:

37.1g of Ca

Explanation:

Hello,

Molecular formula for calcium chloride = CaCl

Molar mass = 40 + 35.5 = 75.5g/mol

Assuming there's one mole of CaCl

1 mole = mass / molar mass

Mass = 1 × 75.5

Mass = 75.5g

75.5g of CaCl contains 40g of Calcium

70g of CaCl will contain x g of Calcium

X = (70 × 40) / 75.5

X = 37.086g

Therefore, 70g of CaCl contains approximately 37.1g of Ca

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yuradex [85]

Answer:

Mix ½ teaspoon apple cider vinegar, ½ teaspoon lemon juice, and 1 tablespoon water, and dip a cotton ball in the liquid. Apply to dark

6 0
3 years ago
A mixture of gases with a pressure of 800.0 mm hg contains 60% nitrogen and 40% oxygen by volume. what is the partial pressure o
klasskru [66]
Hello!

<span>We have the following statement data:
</span>
Data:
P_{Total} = 800 mmHg
P\% N_{2} = 60\%
P\% O_{2} = 40\%
P_{partial} = ? (mmHg)

<span>As the percentage is the mole fraction multiplied by 100:

</span>P =  X_{ O_{2} }*100

<span>The mole fraction will be the percentage divided by 100, thus:
</span><span>What is the partial pressure of oxygen in this mixture? 
</span>
X_{ O_{2} }  =  \frac{P}{100}
X_{ O_{2}} =  \frac{40}{100}
\boxed{X_{ O_{2}} = 0.4}


<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
</span>
In relation to O_{2} :

\frac{P O_{2} }{P_{total}} = X_O_{2}
\frac{P O_{2} }{800} = 0.4
P_O_{2} = 0.4*800
\boxed{\boxed{P_O_{2} = 320\:mmHg}}\end{array}}\qquad\quad\checkmark
<span>
Answer:
</span><span>b. 320.0 mm hg </span>
7 0
3 years ago
A. Energy is transferred to different forms
Luden [163]

Answer:

A. Energy is transferred to different forms .

Explanation:

Hello!

In this case, we need to consider the law of conservation of mass and energy which states that mass and energy cannot be neither created nor destroyed, just modified; it means we can rule out B. and C. so far.

Moreover, since D. is actually true for combustion reactions because they are used to provide energy in industrial operations, this is not the concern here because a combustion reaction is not considered.

Therefore the correct option is A. Energy is transferred to different forms as the energy provided by Rose is transferred to the pendulum system .

Best regards!

3 0
3 years ago
Which source is most likely to be impartial?
Nina [5.8K]
The answer is A I’m not 100 percent sure tho
6 0
3 years ago
A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4
natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M

8 0
3 years ago
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