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Ilya [14]
3 years ago
9

If I leave 750 mL of 0.75 M sodium chloride solution uncovered on a windowsill and 150 mL of the solvent evaporates, what will t

he new concentration of the sodium chloride solution be? M1V1 = M2V2
Chemistry
1 answer:
maks197457 [2]3 years ago
3 0

the answer to your question is

M1V1=M2V2

V2=750-150=600 ml

0.75M*750 ml = M2*600

M2=0.75*750/600 ≈ 9.38 M


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How many moles of O2 are required to generate 18 moles of H2O in the given reaction? 2C8H18 + 25O2 16CO2 + 18H2O
Veronika [31]
There's a slight error in your equation. I think you were trying to present it like this:

2C8H18 + 25O2 -> 16CO2 + 18H2O

Mole Ratio
O2 : H20
25 : 18
? moles : 18 moles
(18/18)×25 : 18 moles

25 moles : 18 moles

Final answer would be 25 moles of O2. :)

If you have any doubts that you want to clarify with me, please ask me! :)
I will do my utmost best to help you.
7 0
4 years ago
Read 2 more answers
A 3000 MWt fast reactor has a 42% efficiency. This reactor operates for 23 months followed by a 1 month down time for refueling
n200080 [17]

Answer:

capacity factor = 0.952

Availability factor = 0.958

Explanation:

1) capacity factor

capacity factor = actual power output /  maximum power output

                        = (actual power output)/(efficiency * rated power output)

                       = \frac{1200}{\frac{42}{100}*3000}

= 0.952

2) Availability factor

Availability factor  = Actual operation time period/ total time period

                            = 23/24 = 0.958

8 0
3 years ago
What is the molarity of a solution that contains 0.202 mol KCl in 7.98 L solution?
mr Goodwill [35]

Explanation:

molarity = no. of moles of solute/solution in litres

molarity =0.202/7.98

=0.025 M

8 0
3 years ago
1. Given the specific heat of lead is 0.129 J/g.C and that it takes 93.4J of energy to
zheka24 [161]

Answer: 40 grams

Explanation:

The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Since Q = 93.4J

M = ?

C = 0.129 J/g.C

Φ = 40.4°C - 22.3°C = 18.1°C

Then, Q = MCΦ

Make Mass, M the subject formula

M = Q/CΦ

M = (93.4J) / (0.129 J/g.C x 18.1°C)

M = 93.4J / 2.33J/g

M = 40 g

Thus, the mass of the lead is 40 grams

8 0
3 years ago
2. How many mi hr is 30km/s?​
dalvyx [7]

The answer is 67 108.0888km/s.

4 0
4 years ago
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