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3 years ago

What is the reactant in the following equation?

1 answer:

4 0

To remember what the reactant is, it always comes before the yielding sign (arrow). The elements after the arrow are known as the 'products'.
So, with this information, let's look for our reactants.
Remember, the reactants are the elements BEFORE the yielding sign (arrow).
We have Hydrogen and Oxygen before the arrow.

Your answer is:
Hydrogen + Oxygen

I hope this helps!

You might be interested in

Sodium and chlorine react to form sodium chloride. If there are 1.4 moles of sodium used, how many moles of chlorine were requir

sammy [17]

Answer:

0.7 moles of Chlorine gas is required.

Explanation:

The reaction is balanced as follows:

2Na + $Cl_{2}$ ------> 2NaCl

According to stoichiometry,

2 mole Sodium reacts with 1 mole Chlorine gas

∴1 mole Sodium reacts with 1/2 moles of Chlorine gas

∴1.4 mole sodium reacts with 1.4/2 moles of Chlorine gas

= 0.7 moles of Chlorine gas

So, 0.7 moles of Chlorine gas is required.

3 0

3 years ago

What are three other elements that have 8 valance electrons.

Rina8888 [55]

8 valence electrons means that the element is stable. When we hear stable, we know the group to look at! Noble gases all have 8 valence electrons making them stable and have a full octet.

Here are some:-

Krypton
Argon
Neon

5 0

3 years ago

Read 2 more answers

When a pendulum swings, at which point is kinetic<br> energy highest:

Anna [14]

Answer:

Explanation:

3 0

3 years ago

Katerina is going to perform a reaction between Hydrochloric Acid (HCl) and solid Zinc. She needs to use 5 mols of HCl, how many

chubhunter [2.5K]

Answer:

182.3 g

Explanation:

number of mols of HCl = 5 mols

molecular weight of HCl = 36.46 g/mol

m = mass of HCl = number of mols x molecular weight

m = 5 mols * 36.46 g/mol

m = 182.3 g

8 0

3 years ago

A sample of an unknown compound was decomposed and found to be composed of 1.36 mol oxygen, 4.10 mol hydrogen, and 2.05 mol carb

AfilCa [17]

We are given the number of moles:

O = 1.36 mol

H = 4.10 mol

C = 2.05 mol

To get the empirical formula, first divide everything by the smallest number of moles = 1.36 mol. So that:

O = 1 mol

H = 3 mol

C = 1.5 mol

Next step is to multiply everything by a number such that all will be a whole number. In this case, multiply by 2 to get a whole number for C, so that:

O = 2 mol

H = 6 mol

C = 3 mol

Therefore the empirical formula of the compound is:

C3H6O2

8 0

4 years ago