Answer:
~69.744 moles of Ca
Explanation:
Using Avogadro's constant , we know that:
1 mole = 6.022 x 10^23 atoms
S0, the number of moles in 4.20 x 10^25 atoms of Ca:
=(4.20 x 10^25 x 1 )/(6.022 x 10^23)
~69.744 moles of Ca
Q2:How many atoms are in 0.35 moles of oxygen?
1 mole = 6.022 x 10^23 atoms
S0, the number of atoms in 0.35 moles of oxygen:
=[0.35 x (6.022 x 10^23)]
=2.1077 x 10^23 atoms of Oxygen
Hope it helps:)
1.T
2.F
3.T
I think I think Im not complety sure sorry
<h2><u>QUE</u><u>STION</u></h2>
It refers to a charged particle or atom.
<h2><u>CHOI</u><u>CES</u></h2>
<u>A.</u><u> </u><u>molecule</u>
B. bromine
C. potassium
D. sulfur
<h2><u>ANSWER</u></h2>
<h3><u>C</u><u>.</u><u> </u><u>pottasium</u></h3>
Answer: The percent ionization of a monoprotic weak acid solution that is 0.188 M is 
Explanation:
Dissociation of weak acid is represented as:
cM 0 0
So dissociation constant will be:
Give c= 0.188 M and 
= ?
Putting in the values we get:
Thus percent ionization of a monoprotic weak acid solution that is 0.188 M is
