Answer:
![\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]](https://tex.z-dn.net/?f=%5CSigma_%7Bk%3D1%7D%5E%7Bn%7D%5B3%28%5Cfrac%7B10%7D%7B9%7D%20%29%5E%7Bk-1%7D%5D)
Step-by-step explanation:
A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.
The first term is denoted by a and the common ratio is denoted by r.
A geometric sequence has the form:
a, ar, ar², ar³, . . .
The nth term of a geometric sequence is 
Therefore the sum of the first n terms is:
Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:
The answer is $9,100
6,500 x .08 = 520
520 x 5 = 2,600
2,600 + 6,500 = 9,100
Hope this helps!
The answer is $12.5 for 10 bottles
Answer:
56,500,000.
Step-by-step explanation:
56,477,812 rounded to the nearest hundred thousand:
The 4 is in the hundred thousands place, so we'll look at the next digit to the right of that, which is the 7:
56,<u>4</u>77,812
Since 7 is more than 5, we'll have to go up a number, which will be the 4. Afterwards, we'll have to replace all the digits after the 4 with zeros.
56,500,000.
Answer:
distributive property
Step-by-step explanation:
2(a+5)
2 is being distributed
