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3 years ago

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A circle has a radius of 2.5 cm. What is the diameter of this circle in cm? Record your answer in Blank 1. What is the circumfer

ence of this circle? Record your answer in Blank 2 (\large \pi is almost 3.14)______________?

1 answer:

Eva8 [605]3 years ago

3 0

Answer:

The diameter is 5 cm and the circumference is diameter x pi

Step-by-step explanation:

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Use the data set to determine which statements are correct. Check all that apply 35,41,18,75,36,21,62,29,154,70

SCORPION-xisa [38]

Answer:

The median is 38.5

The lower quartile is 29

There is an outlier (154)

The upper quartile is 70

and

The interquartile range is 70 - 29= 41

Hope this helps u!

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-125%7D%20%3D" id="TexFormula1" title="\sqrt[3]{-125} =" alt="\sqrt[3]{-125}

Ket [755]

Answer:

It is -5

Step-by-step explanation:

Have a nice day.

5 0

3 years ago

Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th

RSB [31]

Answer:

The volume of the solid is:

$\displaystyle\frac{19\pi}{6}$

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

$x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1$

Since the region is the one for $x\ge 0$ then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

$\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx$

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so $8x-9-x^2$ (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

$\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx$

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the $2\pi$ and distributing the x:

$=\displaystyle2\pi \int_0^19x-8x^2-x^3dx$

Then use the basic rule to integrate:

$=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1$

Then evaluate the antiderivative in the limits and subtract:

$=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}$

So the volume of the solid is $\displaystyle\frac{19\pi}{6}$

4 0

3 years ago

Write the equation for the line that has a slope of -4 and passes through the point (-2, 2)

Fynjy0 [20]

Answer:

y = -4x - 6

Step-by-step explanation:

y = -4x + b

2 = -4(-2) + b

2 = 8 + b

-6 = b

5 0

3 years ago

Read 2 more answers

Which equation represents the line that passes through (5,8) and (9,2)

Dahasolnce [82]

ASSUMING This is a straight line so we gotta the formula for a straight line which is y=mx+b, where m represents the slope and b represents the y intercept.

First, we know this line passes through (5,8) and (9,2) we can use these for finding the equations. When we know two points, we use this formula:

y-y=m(x-x)

The first y is 8 and the second one is 2
The first x is 5 and the second one is 9

Plug it in:

8-2=m(5-9)
6=m(-4)
6/-4=m <— simplify this
m= -3/2

*NOTE: another way to find m is by calculating it (y-y)/(x-x)

Now we know m, we have to find b.
All you gotta do is plug everything you know back into the equation y=mx+b

y=mx+b
y=-3/2x+b <— now plug in a point we know(x,y)

8=-3/2(5)+b
8=-15/2+b
8-(-15/2)=b
b=8+15/2
b=16/2+15/2
b=31/2 (now you can write be as a fraction or a decimal in your equation, depending on what your teacher told you to use)
*NOTE: it is best to use fractions instead of decimals as it is more accurate sometimes.

Now we know all the variables that need to be known, we just need to rewrite the formula of the equation so the teacher can see.

m=-3/2
b=31/2

We don’t need to plug in x or y since it could have different values (since a straight line has MANY co-ordinates)

SO OUR EQUATION IS=
y=(-3/2)x+31/2

Hope you understand this, feel free to ask me anything!

6 0

3 years ago