Answer- KG⎯∥JH⎯
the given figure is a trapezium in which CF||DE
Reflection of figure CDEF and shifting it by 3 units does not change the shape of the figure but changes only its position in the x-y plane.
so, the shape of the figure GHJK will be same as that of CDEF.
so sides, KG⎯∥JH⎯
Answer:
yes, the centroid is where the medians meet
<em>hope this helps!</em>
<em>have a great day :)</em>
Answer:
Step-by-step explanation:
Use the formula 
to find the sum of the angles in a polygon, given <em>n</em> sides. This formula tells us the angles of this pentagon must add to 540 (
).
So, we can setup an equation:
Solve for z:
Combine like terms
Subtract 200
Divide by 5
Therefore, the value of z = 68.
Answer:
<em>3y+5x=6</em>
Step-by-step explanation:
<u>Equation of the Line</u>
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:
The line passes through the points (6,-8) and (-3,7), thus:
Simplifying:
Multiplying by 3:
Moving all the variables to the left side:
3y + 5x = 30 - 24
3y + 5x = 6
Question 6
Given:
QR = RS
QR = x + 6
RS = 4x
To find:
Length of line segment QS
Steps:
We know QR = RS, so substituting we get,
x + 6 = 4x
6 = 4x - x
6 = 3x
6/3 = x
2 = x
x = 2
Now,
QS = QR + RS
QS = x + 6 + 4x
QS = 2 + 6 + 4(2)
QS = 2 + 6 + 8
QS = 8 + 8
QS = 16 units
Therefore, the length of QS is 16 units
Question 7
Given:
QR = RS
QR = 2x - 2
RS = 2x
To find:
Length of line segment QS
Steps:
We know that QR = RS, so substituting the values we get,
QR = RS
3x - 2 = 2x
3x - 2 - 2x = 0
3x - 2x = 2
x =2
Now,
QS = QR + RS
QS = 3x - 2 + 2x
QS = 3(2) - 2 + 2(2)
QS = 6 - 2 + 2(2)
QS = 6 - 2 + 4
QS = 4 + 4
QS = 8 units
Therefore, the length of QS is 8 units
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