Answer:
Approximate height of the building is 23213 meters.
Explanation:
Let the height of the building be represented by h.
0.02 radians = 0.02 ×
= 0.02 x (180/)
0.02 radians = 1.146°
10.5 km = 10500 m
Applying the trigonometric function, we have;
Tan θ =
So that,
Tan 1.146° =
⇒ h = Tan 1.146° x 10500
= 2.21074 x 10500
= 23212.77
h = 23213 m
The approximate height of the building is 23213 m.
Answer:
<em>126.01 rad/s^2</em>
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Explanation:
since it starts from rest, initial angular speed ω' = 0 rad/s
angular speed N = 477 rev/min
angular speed in rad/s ω = =
= 49.95 rad/s
angular displacement ∅ = 1.5758 rev
angular displacement in rad/s = = 2 x 3.142 x 1.5758 = 9.9 rad
angular acceleration = ?
using the equation of angular motion
ω^2 = ω'^2 + 2∅
imputing values, we have
2495 = 19.8
= 2495/19.8 = <em>126.01 rad/s^2</em>
Answer: a) electric field will be zero at zero meters apart
b) for smaller charge q, E = 6.048X10^6N/m towards away from the charge,
for bigger charge Q, E = 4.032X10^6N/m
Explanation:
Detailed explanation and calculation is shown in the image below.
