In my county Contra Costa County, California a property (with a value of greater than 15.00) left abandoned after 3 years the County needs to publish in a newspaper the location of the property and try and locate the lawful owners. Often their may be unpaid property taxes and penalties that need to be paid if the owner is found and wishes to reclaim the property. Sometimes due to deaths of previous owners without a trust or will it is difficult to find if their are any heirs to the property. If no one responds within 45 days of the publication the property will belong to the county and no longer claimed. If you feel you have any property or cash that belongs to you every State has a government site called unclaimed property. You can put in your name or a relatives name and if it belongs to you there is a form to be filled out and if you are the rightful owner you will receive it.
Answer:
The starting velocity for ball 1 is 1.00 meter/second. Its ending velocity is 0.25 meter/second.
The change in velocity for ball 1 is 0.25 – 1.00 = -0.75 meter/seconds
Answer:
Explanation:
Given
Flow rate
At one Point
At second Point
Density of water
As Flow is constant therefore
Applying Bernoulli's theorem
as pipe is horizontal therefore
thus
Part 1- The work done by the gas during this process will be 5.65 ×10⁻³ kJ.
Part 2-The heat added to the gas during this process will be 5.65 ×10×10⁻³ kJ.
<h3>What is work done by the gas?</h3>
Work is the product of pressure p and volumes V during a volume change for such a gas. The work seems to be the area under the curve that indicates how the state changes.
The work done under the isothermal process is;
For the isothermal process;
ΔU=0
Hence, the work done, and the heat added by the gas during this process will be 5.65 ×10⁻³ kJ and 5.65 ×10×10⁻³ kJ respectively.
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Answer:
Hello some part of your question is missing below is the missing part
2. What is the force on the charged particle if it is now located at the 0V potential difference line? (mN) (hint: The electric field can be obtained as above using the 0V and -10V equipotential lines.)
answer :
1) 0.8 mN
2) 0.8 mN
Explanation:
Given data:
1) Calculate the force on the charged particle
q = 80 μC , Va = 30v , Vb = 40v, ∝ = 1 m
E = ( Δv ) / ∝
= ( Vb - Va ) / ∝
F = qE
= 80 μC * ( 40 - 30 ) / 1 m
= 800 μC
F = 0.8 mN
<u>2) Calculate the force on the charged particle when it is located at 0V</u>
Va = -10V , Vb = 0V, q = 80 μC, ∝ = 1 m
F = qE
where E = ( 0 - ( -10 ) / 1
F = 80 μC * ( 0 - ( -10 ) / 1
= 800 μC = 0.8 mN