What is the standard unit of resistance?

A sock stuck to the inside of the clothes dryer spins around the drum once every 2.0 s at a distance of 0.50 m from the center o

Rashid [163]

a) 1.57 m/s

The sock spins once every 2.0 seconds, so its period is

T = 2.0 s

Therefore, the angular velocity of the sock is

$\omega=\frac{2\pi}{T}=\frac{2\pi}{2.0}=3.14 rad/s$

The linear speed of the sock is given by

$v=\omega r$

where

$\omega$ is the angular velocity

r = 0.50 m is the radius of the circular path of the sock

Substituting, we find:

$v=(3.14)(0.50)=1.57 m/s$

B) Faster

In this case, the drum is twice as wide, so the new radius of the circular path of the sock is twice the previous one:

$r' = 2r = 1.00 m$

At the same time, the drum spins at the same frequency as before, therefore the angular frequency as not changed:

$\omega' = \omega = 3.14 rad/s$

Therefore, the new linear speed would be:

$v'=\omega' r' = \omega (2r)$

And substituting,

$v'=(3.14)(1.00)=3.14 rad/s = 2v$

So, we see that the linear speed has doubled.

8 0

3 years ago

Two asteroids are found at the same distance from the Sun. However, one asteroid is twice as massive the other. According to New

astraxan [27]

Answer:

IS TWICE THAT OF THE GRAVITATIONAL FORCE BETWEEN THE SMALLER ASTEROID AND THE SUN

Explanation:

The equation for gravitational force is:

$F = G * \frac{m1 * m2}{r^2}$

where G is the gravitational constant.

Given that distance remains constant, and the mass of the bigger asteroid is bigger, we can get the following relation:

$G * \frac{2*m1 * m2}{r^2} = G * \frac{m1 * m2}{r^2}$

Here we can see that multiplying the mass by 2 gives us 2 times the gravitational force for the bigger asteroid.

Thus, the gravitational force for the bigger asteroid and the sun is two times that of the smaller asteroid and the sun.

4 0

3 years ago

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An α-particle has a charge of +2e and a mass of 6.64 × 10-27 kg. It is accelerated from rest through a potential difference that

zzz [600]

Answer with Explanation:

We are given that

Charge on alpha particle=q=2 e= $2\times 1.6\times 10^{-19} C$

1 e= $1.6\times 10^{-19} C$

Mass of alpha particle=m= $6.64\times 10^{-27} kg$

Potential difference,V= $1.97\times 10^6 V$

Magnetic field,B=3.49 T

a.Speed of alpha particle=v= $\sqrt{\frac{2 qV}{m}}$

By using the formula

$v=\sqrt{\frac{2\times 2\times 1.6\times 10^{-19}\times 1.97\times 10^6}{6.64\times 10^{-27}}$

$v=1.38\times 10^7 m/s$

b.Magnetic force,F $=qvB=2\times 1.6\times 10^{-19}\times 1.38\times 10^7\times 3.49=1.5\times 10^{-11} N$

F= $1.5\times 10^{-11} N$

c.Radius of circular path, r= $\frac{mv^2}{F}$

$r= \frac{6.64\times 10^{-27}\times (1.38\times 10^7)^2}{1.5\times 10^{-11}}$

r=0.084 m

5 0

3 years ago

Which of the following is NOT a symptom associated with hypertension?

zepelin [54]

I would say a or d hope this helps haha ( also if you could do brainliest for this that would be AMASINF bc I really want to rank up, u don’t have to tho)

8 0

3 years ago

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A ray at which angle would produce the most glare? A. 59 degrees C. 25 degrees D. 37 degrees

Mkey [24]

<span>A. 59 degrees......
Hope it works</span>

5 0

3 years ago

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