I think this is the answer ----> 8.7 (8.66 rounded)
This question is not correctly written
Complete Question
The Henderson Hawks minor-league baseball team is giving away baseballs an
game. The balls cost $3 each and the towels cost $2 each. The team wants to give away 200 items and have 500 to spend. How many of each item should the team give away Show your
work or explain your reasoning.
Answer:
They should give away 100 balls and 100 towels
Step-by-step explanation:
Let the number of balls = x
Let the number of towels = y
x + y = 200........ Equation 1
y = 200 - x
$3 × x + $2 × y = $5000
3x + 2y = 5000...... Equation 2
3x + 2(200 - x)= 5000
3x + 400 - 2x = 5000
Collect like terms
3x - 2x = 500 - 400
x = 100
Number of balls to be given away = 100
Note:
y = 200 - x
y = 200 - 100
y = 100
Number of towels to be given away = 100
Therefore, they should give away 100 balls and 100 towels
Answer:
C
Step-by-step explanation:
Bro don’t trust me
Answer:
- C The range is the set of all real numbers greater than 0.
Step-by-step explanation:
We see that the function has positive range and no restriction of domain.
A The range is the set of all real numbers less than 0.
- Incorrect, positive values only
B The domain is the set of all real numbers greater than-4.
- Incorrect, the domain can get any value
C The range is the set of all real numbers greater than 0.
- Correct, the range is restricted to positive values
D The domain is the set of all real numbers less than-4.
- Incorrect, no restrictions
One way to do it is with calculus. The distance between any point

on the line to the origin is given by

Now, both

and

attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

Solving for

, you find a critical point of

.
Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.
You have

so indeed, a minimum occurs at

.
The minimum distance is then