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Free_Kalibri [48]
3 years ago
12

Give a counterexample for the statement All square roots are irrational numbers.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
4 0

Answer:

The square root of 4 is 2(not irrational)

The square root of 100 is 10(not irrational

Step-by-step explanation:

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Answer:

first and last

Step-by-step explanation:

Total observations:

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4 0
4 years ago
How to solve and what is the answer
TiliK225 [7]
Two ways: 
1) guess factors(trial and error)
2) use quadratic formula.
If you use this method then a = -3, b = -6 and c = -1


x = -b +/- [sqrt(b^2 -4ac)/2a]
substituting a, b, and c into our equation we get:
x = - (-6)+/- [sqrt ((-6)^2) - 4(-3)(-1))/2 (-3)]
x = + 6 +/- [sqrt (36 -4 (3)/-6)]  if I didnt make a mistake in my signs
x = + 6 +/- [sqrt (36 -12)/-6)]
x = 6 +/- [sqrt (24)/-6]  but sqrt 6 x sqrt of 4 = sqrt 24 hence
x = 6 +/-  [ sqrt 6 x sqrt 4 /-6] that is:
x = 6 +/- [sqrt 6 x 2 /-6 ]
so x = 6 + [sqrt 6 x 2/-6] and x = 6 - [sqrt 6 x 2/-6]

7 0
3 years ago
Twenty times one hundred and one (20 x 101)
Dmitrij [34]

Answer:

2020

Step-by-step explanation:

2020

4 0
3 years ago
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Step-by-step explanation: Calculators answer

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g. Substitution Property

Step-by-step explanation:

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