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Free_Kalibri [48]
3 years ago
12

Give a counterexample for the statement All square roots are irrational numbers.

Mathematics
1 answer:
skelet666 [1.2K]3 years ago
4 0

Answer:

The square root of 4 is 2(not irrational)

The square root of 100 is 10(not irrational

Step-by-step explanation:

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90% of a number is x . What is 100% of the number? Assume x>0
mariarad [96]

Step-by-step explanation:

Let the required number be n

\therefore \:  \frac{90}{100}  \times n = x \\  \\ \therefore \:  \frac{9}{10}   \\  \\  \therefore \:n = \frac{10}{9} x \\  \\  \therefore 100\% \: of\:n = \frac{10}{9} x \times 100\% \\  \\  = \frac{10}{9} x \times \frac{100}{100}  \\  \\  =  \frac{10}{9} x  \\

NOTE: A number is always 100% in itself.

3 0
3 years ago
Find the y-intercept of the line 4x + 8y = 16.
aksik [14]

Answer:

the y intercept is 8

Step-by-step explanation:

3 0
4 years ago
Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.
love history [14]
-2z^2+5z-5; Quadratic trinomial, 3 terms
3 0
3 years ago
The area of the rectangle below is greater than or equal to 18.13 square units. The inequality 3.7w ≥ 18.13 represents this
Katyanochek1 [597]
W>4.9 (NOTE: The greater than sign is supposed to be greater than OR equal to)

You can rewrite the inequality like this because you can simplify the equation to get rid of the 3.7. You do this by dividing both sides of the expression by 3.7, since that’s what the w is being multiplied by.

Hope this helps!
5 0
2 years ago
the weight of an object on mars varies directly as the weight of the object on earth a 90 pound object on earth weighs 34 pounds
Mariulka [41]

We have been given that the weight of an object on the mars varies directly as the weight of the object on earth.  

Let y be weight of an object on Mars and x be weight of an object on Earth.

\\
y=kx

We have been given that the weight of an object on Mars is 34 pounds and weight of the same object on Earth is 90 pounds.

Putting the given values in equation we get

\\
34=k(90)\\
\\
k=\frac{34}{90}=\frac{17}{45}

Therefore, our equation now becomes

\\
y= \frac{17}{45}x

Now we have been given that the weight of an object on Earth is 135 pounds and we have to find the weight of the same object on Mars,

We have been given that \\
x=135

Putting the given values in our equation we get

\\
y= \frac{17}{45}(135)=\frac{17\cdot 135}{45}=17\cdot 3 = 51

Therefore weight of the object on Mars will be 51 pounds.

                                                                             

7 0
4 years ago
Read 2 more answers
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