Answer:the sodium carboxylate salt
Explanation:
The reaction between the carboxylic acid and the sodium hydroxide yields a sodium carboxylate. This sodium carboxylate is an ionic in nature; RCCOO-Na+. This can effectively interact with water and remain in the aqueous phase since it is composed of the carboxylate ion and sodium ion in solution. The aqueous phase always contains water soluble ionic substances of which the sodium carboxylate is a typical example of such.
Random motion of molecules produces a concentration gradient and a net movement of solute as random movement of molecules causes diffusion that causes movement of molecules from high concentration to low concentration . No ATP is required in this process. This causes movement of solute molecules and causes concentration gradient.
Answer: cause oxegeon is harmful then helium
Explanation:
Answer:
50.0mL 0.10M NaOH
Explanation:
The chemical equation of H₂SO₄ with NaOH to reach the first equivalence point is:
H₂SO₄ + NaOH → HSO₄⁻ + Na⁺ + H₂O
<em>Where 1 mole of the H₂SO₄ reacts per mole of NaOH</em>
<em />
The initial moles of H₂SO₄ are:
50.0mL = 0.0500L × (0.10 mol / L) = 0.0050 moles of H₂SO₄
As 1 mole of the acid reacts per mole of NaOH, to reach the first equivalence point we need to add 0.0050 moles of NaOH. As molarity of NaOH is 0.10M, the volume that we need to add to reach 1st equivalence point is:
0.0050 moles NaOH ₓ (1L / 0.10 moles NaOH) = 0.050L NaOH 0.10M =
<h3>50.0mL 0.10M NaOH</h3>
When electrical power is applied to two plates placed inside the water, electrolysis occurs and hydrogen appear on the cathode and Oxygen on anode. It is due to the ideal faradaic efficiency, the amount of hydrogen generated is twice the number of moles of oxygen.
If you look at the equation , reduction occurs at cathode i.e
2 H+ + 2e−<span> → H</span>2
Oxidation occurs at anode
2 H2O → O2 + 4 H+ + 4e<span>−
</span>
Overall reaction
2 H2O(l) → 2 H2(g) + O2(g<span>)
Therefore, </span><span> volume of gas collected over one electrode double the volume of gas collected over the other electrode.</span>
