Answer:
Mg3N2(s) + 6H2O(l) → 3Mg(OH)2(s) + 2NH3(g)
Explanation:
Step 1: Data given
ammonia = NH3
water = H2O
magnesium nitride = Mg3N2
Step 2: The unbalanced equation
Mg3N2(s) + H2O(l) → Mg(OH)2(s) + NH3(g)
Step 3: Balancing the equation
On the left side we have 3x Mg (in Mg3N2), on the right side we have 1x Mg (in Mg(OH)2).
To balance the amount of Mg, we have to multiply Mg(OH)2 by 3
Mg3N2(s) + H2O(l) → 3Mg(OH)2(s) + NH3(g)
On the left side we have 2x N (in Mg3N2), on the right side we have 1x N (in NH3). To balance the amount of N, we have to multiply NH3 by 2
Mg3N2(s) + H2O(l) → 3Mg(OH)2(s) + 2NH3(g)
On the left side we have 2x H (in H2O), on the right side we have 12x H ( 6x in Mg(OH)2 and 6x in NH3). To balance the amount of H we have to multiply H2O (on the left side), by 6.
Now the equation is balanced.
Mg3N2(s) + 6H2O(l) → 3Mg(OH)2(s) + 2NH3(g)
