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Pavlova-9 [17]
3 years ago
14

Solve the equation for y. Then find the value of y for each value of x. y+2x=5; x= -1, 0, 4

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

y = 3, y = 5, y = -1

Step-by-step explanation:

What you do is you substitute the x values into the x.

<em>y + 2(-1) = 5</em>

<em>y + -2 = 5</em>

y = 3

<em>y + 2(0) = 5</em>

y = 5

<em>y + 2(4) = 5</em>

<em>y + 6 = 5</em>

y = -1.

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Step-by-step explanation:

a supplementary angle adds up to 180 degrees. two accute angles would equal to around 90 and two obtuse angles would add up to more than 180. two right angles are perpendicular and they could work but since the question asks about acute and obtuse, its true that one angle must be acute and the other must be obtuse for it to add up to 180.

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3 years ago
Help me with this pls
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1/625 or 0.0016

Step-by-step explanation:

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Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

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2/5 + 1/2

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Option C

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Verified

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